exam p A drawer contains four pairs of socks, with each pair a different color. One sock at a time is randomly drawn from the dr
1 answer:
Answer:
The probability that the maximum number of draws is required is 0.2286
Step-by-step explanation:
The probability that the maximum number of draws happens when you pick <em>different colors in the first four pick</em>.
Assume you picked one sock in the first draw. Its probability is 1, since you can draw any sock.
In the second draw, 7 socks left and you can draw all but the one which is the pair of the first draw. Then the probability is
In the third draw, 6 socks left and you can draw one of the two pair colors which are not drawn yet. Its probability is
In the forth draw, 5 socks left and only one pair color, which is not drawn. The probability of drawing one of this pair is
In the fifth draw, whatever you draw, you would have one matching pair.
The probability combined is 1× ×
×
≈ 0.2286
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so you have:
There's the law where if the number outside your parentheses is negative along with the number in the parentheses; it converts into positive...
-->>x-(-x)
--->>x+(+x)
This being said.....
-->>
-->>>
But remember, you want to simplify it....
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