The area of a kite is (1/2) * x * y, where x and y are the length of the two diagonals. In this case, the length of the two diagonals are 10 ft and 2 ft.
<span>Plug that in the equation, we get 1/2 * 2 * 10. We multiply the 2 and 10 first to get 20, that leaves us with 1/2 x 20, which is 10, so the area of this kite is 10 ft squared.</span>
Diameter= 10 cm
radius = 5 cm
area of circle = πr2
= (3.142)(5)^2
=78.55 cm^2
Step-by-step explanation:
Close. You correctly set up the integrals. When integrating e²ˣ:
∫ e²ˣ dx
½ ∫ 2 e²ˣ dx
½ e²ˣ + C
So the coefficient should be ½, not 2.
[eˣ − ½ e²ˣ]₋₁⁰ + [½ e²ˣ − eˣ]₀¹
[(e⁰ − ½ e⁰) − (e⁻¹ − ½ e⁻²)] + [(½ e² − e) − (½ e⁰ − e⁰)]
1 − ½ − e⁻¹ + ½ e⁻² + ½ e² − e − ½ + 1
-e⁻¹ + ½ e⁻² + ½ e² − e + 1
M<YZW = 63 because in an isosceles triangle, the base angles are congruent. (<X and <YZW are both base angles)
Answer:
The product of two integers is #75# and their sum is #-28#. i dont know if this is helpful
