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2 years ago

The difference between 4,632 and 20,000 is what number?

2 answers:

4 0

We find the difference of the two numbers by subtracting the two numbers given above. It is calculated as follows:

Difference = 20000 - 4632 = 15368

Therefore, the difference between <span>4,632 and 20,000 is 15368.

Hope this answers the question. Have a nice day.</span>

slavikrds [6]2 years ago

3 0

We have to find the difference between these two numbers by subtracting.

20,000 - 4,632 = 15,368

Answer = the difference between these two numbers is 15,368.

Good Luck! :)

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If an arrow is shot upward on Mars with a speed of 56 m/s, its height in meters t seconds later is given by y = 56t − 1.86t2.

Zina [86]

Answer: (a) (i)50.42 m/s (ii) 51.35 m/s (iii) 52.094 m/s (iv) 52.2614 m/s (v) 52.27814 m/s

(b) 54.14 m/s

Step-by-step explanation:

The average speed over the given time interval [a,b]: = $\frac{y(b)-y(a)}{b-a}$

Given: If an arrow is shot upward on Mars with a speed of 56 m/s, its height in meters t seconds later is given by $y = 56t − 1.86t^2.$

(a)

(i) average speed = $\frac{y(2)-y(1)}{2-1}$

$=\frac{56(2)-1.86(2)^2-(56(1)-1.86(1)^2)}{1}$

$=50.42$ m/s

(ii) average speed = $\frac{y(1.5)-y(1)}{1.5-1}$

$=\frac{56(1.5)-1.86(1.5)^2-(56(1)-1.86(1)^2)}{0.5}$

$=51.35$ m/s

(iii) average speed = $\frac{y(1.1)-y(1)}{1.1-1}$

$=\frac{56(1.1)-1.86(1.1)^2-(56(1)-1.86(1)^2)}{0.1}$

$=52.094$ m/s

(iv) average speed = $\frac{y(1.01)-y(1)}{1.01-01}$

$=\frac{56(1.01)-1.86(1.01)^2-(56(1)-1.86(1)^2)}{0.01}$

$=52.2614
$ m/s

(v) average speed = $\frac{y(1.001)-y(1)}{1.001-01}$

$=\frac{56(1.001)-1.86(1.001)^2-(56(1)-1.86(1)^2)}{0.001}$

$=52.27814
$ m/s

(b) $y(1)=56(1)-1.86(1)^2$

$=56-1.86$

$= 54.14$ m/s

3 0

2 years ago

3/4x+3y=12 for x when y=5

Karolina [17]

Solve for x by simplifying both sides of the equation, then isolating the variable.
x = -4
Hope this helps! :)
Happy New Years!

4 0

3 years ago

Find the quotient of 12,3

olga_2 [115]

Divide 12 by 3.your answer should be 4

8 0

3 years ago

Write an expression for "8 times z."

garri49 [273]

Answer: 8z 8(z)

Explanation: well 8 times z is simply 8(z)I don’t really think there is another way

5 0

2 years ago

The sum of the first ten terms of a linear sequence is 145. the sum of the next ten term is 445. find the sum of the first four

chubhunter [2.5K]

The sum of the first four terms of the sequence is 22.

In this question,

The formula of sum of linear sequence is

$S_n =\frac{n}{2}(2a+(n-1)d)$

The sum of the first ten terms of a linear sequence is 145

⇒ $S_{10} =\frac{10}{2}(2a+(10-1)d)$

⇒ 145 = 5 (2a+9d)

⇒ $\frac{145}{5} =2a+9d$

⇒ 29 = 2a + 9d ------- (1)

The sum of the next ten term is 445, so the sum of first twenty terms is

⇒ 145 + 445

⇒ $S_{20} =\frac{20}{2}(2a+(20-1)d)$

⇒ 590 = 10 (2a + 19d)

⇒ $\frac{590}{10}=2a+19d$

⇒ 59 = 2a + 19d -------- (2)

Now subtract (2) from (1),

⇒ 30 = 10d

⇒ d = $\frac{30}{10}$

⇒ d = 3

Substitute d in (1), we get

⇒ 29 = 2a + 9(3)

⇒ 29 = 2a + 27

⇒ 29 - 27 = 2a

⇒ 2 = 2a

⇒ a = $\frac{2}{2}$

⇒ a = 1

Thus, sum of first four terms is

⇒ $S_4 =\frac{4}{2}(2(1)+(4-1)(3))$

⇒ $S_4 =2(2+(3)(3))$

⇒ S₄ = 2(2+9)

⇒ S₄ = 2(11)

⇒ S₄ = 22.

Hence we can conclude that the sum of the first four terms of the sequence is 22.

Learn more about sum of sequence of n terms here

brainly.com/question/20385181

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6 0

1 year ago