12-[20-2(6^2/3•2^2)]

Mathematics

2 answers:

Genrish500 [490]3 years ago

8 0

12-[20-2(6²/3*2²)]

=12-[20-2(36/3*4)]

=12-[20-2(12*4)]

=12-[20-2(48)]

=12-[20-96]

=12-(-76)

=12+76

=88

lutik1710 [3]3 years ago

6 0

$12-\bigg{[}20-2\cdot \bigg{(} \frac{\big{6^2}}{\big{3}} \cdot2^2\bigg{)}\bigg{]}=12-\bigg{[}20-2\cdot \bigg{(} \frac{\big{36}}{\big{3}} \cdot4\bigg{)}\bigg{]}=\\\\=12-(20-2\cdot 12 \cdot4)=12-(20-96)=12-(-76)=12+76=88$

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