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labwork [276]
3 years ago
10

Determine the number of possible solutions for a triangle with A= 30 a=20 and b=16

Mathematics
2 answers:
Nat2105 [25]3 years ago
8 0

Answer:

1 Solution on edge

Step-by-step explanation:

Bess [88]3 years ago
4 0
The answer is: Two possible solutions which are (0.53, 37.19)

Explanation:

Given:
A = 30° 
<span>a = 20 </span>
<span>b = 16 </span>

Now use the law of Cosines:
a² = b² + c² - 2bc*cos(A)

Plug in the values:

20² = 16² + c² - (2*(16)*c*cos(30))
<span>400 = 256 + c² - 32c(0.866) </span>
<span>400 = 256 + c² - 27.71c </span>
<span>c² - 27.71c = 400 - 256 </span>
<span>c² - 27.71c = 144 </span>
<span>c² - 27.71c + 191.96 = 144 + 191.96 </span>
<span>(c - 18.86)² = 335.96 </span>
<span>c - 18.86 = √336.95 </span>
<span>c - 18.86 = ± 18.33 </span>
<span>c = 18.86 ± 18.33 </span>

<span>If c = 18.86 + 18.33, then </span><span>c = 37.19 </span>

<span>If c = 18.86 - 18.33, then </span><span>c = 0.53 </span>

<span>c = (0.53, 37.19) Two solutions!</span>
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Answer:

<u>After four games, a player can lose up to $ 16 to win up to $ 26. These are the probabilities for every game:</u>

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Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

If three coins land "heads" the player wins $ 10

If two coins land "heads" the player wins $ 5

Cost of playing = $ 4

2.  What is the player's expected outcome after four games?

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Now, let's calculate the player's expected outcome, as follows:

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After four games, a player can lose up to $ 16 to win up to $ 26. These are the probabilities for every game:

1/8 or 12.5% of landing three "heads"

3/8 or 37.5% of landing two "heads"

4/8 or 50% of landing no or only one "head".

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Read 2 more answers
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