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Ierofanga [76]
3 years ago
11

Based on the spinner shown, what is the probability of the next spin landing on an even

Mathematics
1 answer:
egoroff_w [7]3 years ago
6 0

Answer:

There is a six out of eight (6/8) chance of it being an even number

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Find the missing length indicated. Show ur work
Semenov [28]
45/35=54/54-x
9/7=54/54-x
9(54-x)=378
54-x=42
x=12

Hope my answer helped u :)
8 0
3 years ago
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The hypotenuse of a right triangle is 34 inches. One leg of the triangle is 14 inches less than the other leg. In simplified for
Karolina [17]
You can use the equation

{(x + 14)}^{2}  +  {x}^{2}  =  {34}^{2}
to find the lenth of the legs

x = leg 1
x + 14 = leg 2
6 0
3 years ago
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I solved 4, the answer is 11, seconds: 5x+4(x-3)=87 = x=11, but I don't know how to solve number 5, please anyone explain how to
liq [111]

The answer x = 11 is correct for problem 4. Nice work.

Use this x value to find the answer in problem 5. From problem 4, we're told that Romeo runs at a speed of 5 m/s. If he runs for x = 11 seconds,then he runs a total distance of:

5*x =(5 m/s)*(x meters) = (5 m/s)*(11 seconds) = 5*11 = 55 meters

The answer to problem five is 55 meters

8 0
3 years ago
What is 247,039 rounded to the nearest thousand
omeli [17]
Pretty sure the answer is 247,000
5 0
3 years ago
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Evaluate the line integral c y3 ds,<br> c.x = t3, y = t, 0 ≤ t ≤ 3
Temka [501]
\displaystyle\int_{\mathcal C}y^3\,\mathrm dS=\int_{t=0}^{t=3}t^3\sqrt{1^2+(3t^2)^2}\,\mathrm dt=\int_0^3t^3\sqrt{1+9t^4}\,\mathrm dt

Take u=1+9t^4 so that \mathrm du=36t^3\,\mathrm dt. Then

\displaystyle\int_{\mathcal C}y^3\,\mathrm dS=\frac1{36}\int_{u=1}^{u=730}\sqrt u\,\mathrm du=\frac{730^{3/2}-1}{54}
7 0
3 years ago
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