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Makovka662 [10]
3 years ago
5

The measures of the angles of triangle ABC are given by the expression and the table

Mathematics
2 answers:
n200080 [17]3 years ago
8 0
In a triangle all the angles add up to 180  degrees.So we know that
(6x-1)+20+(x+14)= 180 
6x+x+14-1+20=180
    v        v
  7x +   13 + 20= 180
                 v
        7x + 33=180
               -33   -33
                  0     147
        7x/7    =   147/7
           x      =       21
x=21
Then you substitute:
(6x-1)       (x+14)
(6×21-1)    (21+14)
    v                  v
  126-1           35
125 degrees / 35 degrees
125+35+20=180
OlgaM077 [116]3 years ago
8 0
The measurement of angle A=125 degrees
the measurement of angle C= 35 degrees

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Solve the system by substitution.<br> -2y - 10 = x<br> - 10x - y = -14
masya89 [10]

Answer:

x=2 and y=−6

sorry this is pretty long, I did not know if you needed the steps or not

Step-by-step explanation:

−2y−10=x;−10x−y=−14

Solve−2y−10=x for x

−2y−10=x

−2y−10+−x=x+−x

−x−2y−10=0

−x−2y−10+2y=0+2y

−x−10=2y

−x−10+10=2y+10

−x=2y+10

-x/-1=2y+10/-1

x=−2y−10

Substitute−2y−10 for x in−10x−y=−14

−10x−y=−14

−10(−2y−10)−y=−14

19y+100=−14

19y+100+−100=−14+−100

19y=−114

19y/19=-114/19

y=-6

Substitute−6 for y in x=−2y−10

x=−2y−10

x=(−2)(−6)−10

x= 2

x=2 and y=−6

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3 years ago
A certain virus infects one in every 200 people. a test used to detect the virus in a person is positive 70​% of the time when t
V125BC [204]

We're told that

P(A)=\dfrac1{200}=0.005\implies P(A^C)=0.995

P(B\mid A)=0.7

P(B\mid A^C)=0.05

a. We want to find P(A\mid B). By definition of conditional probability,

P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}

By the law of total probability,

P(B)=P(B\cap A)+P(B\cap A^C)=P(B\mid A)P(A)+P(B\mid A^C)P(A^C)

Then

P(A\mid B)=\dfrac{P(B\mid A)P(A)}{P(B\mid A)P(A)+P(B\mid A^C)P(A^C)}\approx0.0657

(the first equality is Bayes' theorem)

b. We want to find P(A^C\mid B^C).

P(A^C\mid B^C)=\dfrac{P(A^C\cap B^C)}{P(B^C)}=\dfrac{P(B^C\mid A^C)P(A^C)}{1-P(B)}\approx0.9984

since P(B^C\mid A^C)=1-P(B\mid A^C).

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