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Marianna [84]
3 years ago
9

Y= 3x+13 y=x-3 How do you solve this equation?

Mathematics
2 answers:
ra1l [238]3 years ago
6 0

Answer:

x=-5 & y=-2

Step-by-step explanation:

y= 3x+13

y= x-3

x-3=3x+13

-3=2x+13

-10=2x

x=-5

then

y=3(-5)+13

y=-15+13

y=-2

Gemiola [76]3 years ago
3 0

Answer:

x=-8, y=-11. (-8, -11).

Step-by-step explanation:

y=3x+13

y=x-3

-----------

3x+13=x-3

3x-x+13=-3

2x+13=-3

2x=-3-13

2x=-16

x=-16/2

x=-8

y=-8-3=-11

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13. Write an equation for the given function given the amplitude, period, phase shift, and vertical shift.
Paul [167]

Answer:

y=4sin(\frac{2\pi(t+\frac{4}{3}\pi ) }{4\pi } )-2

Step-by-step explanation:

Let's start with the original function.

y=a sin\frac{2\pi t}{T}

We can immediately fill in the amplitude 'a' and period 'T' , as the question defines these for us, and provides values for 'a' and 'T', 4 and 4\pi respectively.

y=4sin(\frac{2\pi t}{4\pi } )

Now we only have phase shift and vertical shift to do. Vertical shift is very easy, you can just add it to the end of the right side of the expression. A positive value will shift the graph up, while a negative value will move shift the graph down. We have '-2' as our value for vertical shift, so we can add that on as so:

y=4sin(\frac{2\pit }{4\pi } )-2

Now phase shift the most complicated of the transformations. Basically, it is just movement left or right. A negative phase shift moves the graph right, a positive phase shift moves the graph left (I know, confusing!). Phase shift applies directly to the x variable, or in this case the t variable. To achieve a -4/3 pi phase shift, we need to input +4/3 pi into the function, because of the aforementioned negative positive rule. Here is what the function looks like with the correct phase shift:

y=4sin(\frac{2\pi(t+\frac{4}{3}\pi ) }{4\pi } )-2

This function has vertical shift -2, phase shift -4/3 \pi, amplitude 4, and period 4\pi.

Desmos.com/calculator is a great tool for learning about how various parts of an equation affect the graph of the function, If you want you can input each step of this problem into desmos and watch the graph change to match the criteria.

8 0
2 years ago
PLEASE HELP IM BEING TIMED!!! WILL MARK BRAINLIEST FOR CORRECT ANSWER!!! 100PTS!!!
amid [387]

Answer:

B and D.

Step-by-step explanation:

We know that when we added the two functions together, we get:

h(x)=-x+9

However, when we multiplied them together, we get:

j(x)=-9x

Let's first consider what we can determine from this.

If we add them together, we get a linear equation. However, this doesn't mean that our two original functions are linear since if we have, say, -x^2 and x^2-x+9, they will cancel and form a linear equation if we add them together.

<em>However</em>, since we know that if we multiply the two functions together, we get a linear equation, this means that both our original functions must be linear.

<em>But</em>, if we multiplied two linear functions, then we should get a quadratic, since x times x will yield x².

Therefore, this means that one of our linear functions is a horizontal line with no x variable. This is the only way to have a linear equation when multiplied.

Therefore, we have determined that both of our original functions are linear functions, and one (only one of them) is a horizontal line.

Let's go through each of the answer choices.

A) Both functions must be quadratic.

This is false as we determined earlier. If this was true, then the resulting function should be a quartic and not a line. A is false.

B) Both functions must have a constant rate of change.

Remember that all linear equations have a constant rate of change.

Since we determined that both our original functions are linear equation, this means that both our functions will have a constant rate of change.

So, B is true.

C) Both functions must have a y-intercept of 0.

Remember that one of our functions is a horizontal line.

If the y-intercept was 0, then the equation of our horizontal line will be:

y=0

And we know that anything multiplied by 0 will give us 0. However, the product of our function is -9x.

So, C cannot be true.

Rather, only our linear equation (not the horizontal line) may have a y-intercept of 0.

D) The rate of change of either f(x) or g(x) must be 0.

Remember that we determined that one of our lines must a horizontal.

Remember that horizontal lines have a slope of 0. In other words, the rate of change is 0.

So, D is true.

E) The y-intercepts of f(x) and g(x) must be opposites.

Well, since B and D is are true, this must be false since we can only select two options ;D

But, we can think about this. Note that if we multiply the two functions, we have a function <em>without</em> a y-intercept.

Remember that our horizontal line is <em>not</em> 0. So, the y-intercept of the horizontal line is a number.

So, the opposite of a number is another number.

So, if we multiply two non-zero numbers, we <em>must</em> get another number.

However, from our product, j(x)=-9x, we don't have another number. The y-intercept from this is 0.

Therefore, the two y-intercepts <em>cannot</em> be opposites of each other. If it was so, then we should have a y-intercept. So, E must be false.

In fact, this means that the y-intercept of our line (not the horizontal one) <em>must </em>be 0.

So, our answers are B and D.

And we're done!

Edit: Some (minor) errors in reasoning. Sorry!

4 0
3 years ago
Read 2 more answers
Who knows the area of this ? #struggleatmath
photoshop1234 [79]
I think it’s 6. There are 4 squares and 4 triangles. 2 triangles put together turn into a square, so that would make 2 extra squares. 4+2=6.
8 0
3 years ago
Simplified (4x3 - 5x2 + 3x) + (-2x3 - x2 + 6x)
bogdanovich [222]

Answer:

<em>Answer is</em><em> </em><em>imaginary</em><em> </em><em>root</em><em>s</em>

Step-by-step explanation:

({4x}^{3}  -  {5x}^{2}  + 3x) + ( -  {2x}^{3}  -  {x}^{2}  + 6x) \\ 2 {x}^{3}  - 6 {x}^{2}  + 9x = 0 \\ dividing \: by \: x \\ 2  {x}^{2}  - 6x + 9 = 0 \\ dividin g\: by \: 2 \\  {x}^{2}  - 3x +  \frac{9}{2}  = 0 \\ shifting \: the \: constant \: term \: on \: right \: side \\  {x}^{2}  - 3x =  -  \frac{9}{2}  \\ adding \:  \frac{1}{2}  \times (coefficient \: of \: x) \: whole \: square \\

On solving the above mentioned equation we get some imaginary values.

<em> </em><em> </em><em> </em><em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

6 0
2 years ago
What is the equation for the line?<br><br><br><br> Enter your answer in the box.
laila [671]
(0,0),(2,16)
slope = (16 - 0) / (2 - 0) = 16/2 = 8

y = mx + b
slope(m) = 8
and since the line goes thru the origin, the y int is 0

in y = mx + b form, the slope is in the m position and the y int is n the b position....so ur equation is :
y = 8x + 0 which can be written as y = 8x <==
5 0
3 years ago
Read 2 more answers
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