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Soloha48 [4]
3 years ago
10

The capacity of a small glass is 120 ml. how many small glasses can be completely filled from a 2l pitcher of water?

Mathematics
2 answers:
agasfer [191]3 years ago
6 0
2000 milliliters or 16 and a half small glasses.
Harman [31]3 years ago
4 0
Total volume of pitcher = 2 l
Capacity of a small = 120 ml

2000 ml / 120 ml
200 / 12
16.5

It needs 16 full of cups and half cup
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Name three other common multiples of 8 and 12
Sladkaya [172]

The first few multiples of 8 are: 8, 16, 24, 32, 40, and 48. The first multiples of 12 are: 12, 24, 36, 48, 60, and 72.

Common multiple of 8 and 12 are 24 and every subsequent multiple of 24.

As 8×3=24

12×2=24

So 24 is a common multiple of 8 and 12 this means the other common multiples of 8 and 12 are the multiples of 24 like 48, 72, 96 etc.

3 0
1 year ago
Jaden can read 18 pages in 1/3 of an hour. How many pages can he read in 2 hours
algol [13]
Answer is 108 pages. 1/3 of an hr is 20 min. 20*3=60 which is an hr. 3+3=6. So then you get 6*18=108.
8 0
3 years ago
You have 8 times as many dimes as nickels. You have 18 dimes
fenix001 [56]

Answer:

$1.70

Step-by-step explanation:

Let the number of nickels be  x.

Thus, by the problem statement, the number of dimes is  [/tex] 8 \cdot x = 8x. [/tex]

Therefore, there are 8x + x = 9 coins in total. To find what x is, we need to solve the equation 9x = 18. This can be done by dividing both sides by 9 which gives x=2. Plugging these values in tells us that there are 2  nickels and 16 dimes. (Test it out!) Thus, the nickels are worth 2 \cdot 5 = 10 cents and the dimes are worth 16 \cdot 10 = 160 cents, so in all, you have 10 + 160 = 170 cents which is $1.70.

Hope this helps :)

7 0
2 years ago
4 2/3 x 4/5 x 8 1/3 =
Sliva [168]

the answer is a repeating decimal 31.1111111111 but just put 31.1

5 0
4 years ago
Find the next term is in the explicit and recursive rule for the in term of the sequence. NO LINKS!!!
BARSIC [14]

9514 1404 393

Answer:

  5) 729, an=3^n, a[1]=3; a[n]=3·a[n-1]

  6) 1792, an=7(4^(n-1)), a[1]=7; a[n]=4·a[n-1]

Step-by-step explanation:

The next term of a geometric sequence is the last term multiplied by the common ratio. (This is the basis of the recursive formula.)

The Explicit Rule is ...

  a_n=a_1\cdot r^{n-1}

for first term a₁ and common ratio r.

The Recursive Rule is ...

  a[1] = a₁

  a[n] = r·a[n-1]

__

5. First term is a₁ = 3; common ratio is r = 9/3 = 3.

Next term: 243×3 = 729

Explicit rule: an = 3·3^(n-1) = 3^n

Recursive rule: a[1] = 3; a[n] = 3·a[n-1]

__

6. First term is a₁ = 7; common ratio is r = 28/7 = 4.

Next term: 448×4 = 1792

Explicit rule: an = 7·4^(n-1)

Recursive rule: a[1] = 7; a[n] = 4·a[n-1]

7 0
3 years ago
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