Question

A line has a slope of -3/5. Which ordered pairs could be points on a parallel line? Select two options.

Answer 1

Answer:

A,d

Step-by-step explanation:

took the test

Answer 2

The question is missing the options. The options are:

(A) (-8, 8) and (2, 2)

(B) (-5, -1) and (0, 2)

(C) (-3, 6) and (6.-9)

(D) (-2, 1) and (3,-2)

(E) (0, 2) and (5,5)

Answer:

Options (A) and (D)

Step-by-step explanation:

Given:

A line with slope (m) = $-\frac{3}{5}$

Now, a parallel line to the given line will have the same slope.

So, let us check each of the given options.

Option (A)

(-8, 8) and (2, 2)

The slope of line passing through two points $(x_1,y_1)\ and\ (x_2,y_2)$ is given as:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Now, the slope of a line passing through (-8, 8) and (2, 2) is given as:

$m_1=\frac{2-8}{2-(-8)}=\frac{-6}{10}=-\frac{3}{5}$

So, $m=m_1$

Therefore, option (A) is correct.

Option (B): (-5, -1) and (0, 2)

The slope of a line passing through (-5, -1) and (0, 2) is given as:

$m_2=\frac{2-(-1)}{0-(-5)}=\frac{3}{5}$

So, $m\ne m_2$

Therefore, option (B) is not correct.

Option (C): (-3, 6) and (6, -9)

The slope of a line passing through (-3, 6) and (6, -9) is given as:

$m_3=\frac{-9-6}{6-(-3)}=\frac{-15}{9}=-\frac{5}{3}\ne m$

Therefore, option (C) is not correct.

Option (D): (-2, 1) and (3, -2)

The slope of a line passing through (-2, 1) and (3, -2) is given as:

$m_4=\frac{-2-1}{3-(-2)}=-\frac{3}{5}=m$

Therefore, option (D) is correct.

Option (E): (0, 2) and (5, 5)

The slope of a line passing through (0, 2) and (5, 5) is given as:

$m_5=\frac{5-2}{5-0}=\frac{3}{5}\ne m$

Therefore, option (E) is not correct.

Hence, only options (A) and (D) are correct.