Value of x to 3sf<br> area is root 4/2^2 and sides are (x+2) and (2x-3) and angle is 45°

3, 10, 17, 24. what is the 50th term in the sequence

Kamila [148]

Check if you can write an equation relating the term number to the actual value
n1=3
n2=10 = 3+7
n3= 17 = n2+7 = n1+7+7 = n1 +2*7
n4= 24 = n1+3*7

so you will notice a pattern
for the x-th term

n_x =3+(x-1)*7

the 50th term would be n_50 = 3+(50-1) * 7

4 0

2 years ago

What is the x intercept of 4x+6y=3x+8?

Lady bird [3.3K]

6y = - x + 8
y = - 1/6x + 4/3

y intercept = 4/3

3 0

3 years ago

A cell phone company tests 75 cell phones and finds that 3 of them have defects. Out of 450 cell phones, how many would you expe

Hoochie [10]

Answer:

18 cellphones

Step-by-step explanation:

75 x 6= 450

3 x 6= 18

3 0

3 years ago

If the volume of a cube is 8cm^3 what is the surface area of the cube

Varvara68 [4.7K]

Answer:

i am sorry if it is wrong my answer is 1,536

Step-by-step explanation:

so if i am correct 8cm³ the formula for a surface area of a cube is:

SA=s³

6 0

3 years ago

According to a study conducted in one city, 39% of adults in the city have credit card debts of more than $2000. A simple random

Butoxors [25]

Answer:

The sampling distribution of the sample proportion of adults who have credit card debts of more than $2000 is approximately normally distributed with mean $\mu = 0.39$ and standard deviation $s = 0.0488$

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In this question:

$p = 0.39, n = 100$

Then

$s = \sqrt{\frac{0.39*0.61}{100}} = 0.0488$

By the Central Limit Theorem:

The sampling distribution of the sample proportion of adults who have credit card debts of more than $2000 is approximately normally distributed with mean $\mu = 0.39$ and standard deviation $s = 0.0488$

5 0

2 years ago

Value of x to 3sf area is root 4/2^2 and sides are (x+2) and (2x-3) and angle is 45°