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marissa [1.9K]
3 years ago
8

A black rooster mates with a white hen. Based on their genotypes, the chance that the offspring will be checkered is 100 percent

.
What is the rooster’s genotype? A) BB B) Bb C) bb D) BW
What is the hen’s genotype? A) WW B) Ww C) ww D) BW
Biology
1 answer:
Viktor [21]3 years ago
7 0
Well, since the phenotype is checkered, we assume that there is codominance where offspring phenotype is a mix of the parents' phenotypes.  If the offspring phenotype is a blend between the two parents', then there is incomplete dominance.

Genotypes of codominant parents is usually represented by upper case letters B and W, and the mixed genotype would be BW.

Since the genotype BW is 100%, the rooster's genotype can only be BB and the hen's genotype can only be WW to result in 100% BW.

The correspond Punnett square is therefore
       B     B
W  BW  BW
W  BW  BW

By the way, apparently that this example is academically made up, there are no checkered chickens.  I don't know if this is true, since I don't raise enough chickens to verify this.  :)

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