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Softa [21]
3 years ago
11

Graph 4x^2-4x-8/2x-2

Mathematics
1 answer:
Leto [7]3 years ago
6 0

\dfrac{4x^2-4x-8}{2x-2}=\dfrac{4\left(x^2-x-2\right)}{2(x-1)}\\\\=2\cdot\dfrac{(x-2)(x+1)}{x-1}\qquad\text{no factors cancel}\\\\=2x-\dfrac{4}{x-1}\qquad\text{curve with slant, vertical asymptotes}

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Solve for b2 in A = 1/2 h ( b1 + b2 ), if A = 16, h = 4, and b1 = 3.
Katarina [22]

Hello from MrBillDoesMath!

Answer:

b2 = 5  


Discussion:

A = 1/2 h (b1 + b2) .

Substituting A = 16, h = 4, and b1=3 in the above formula gives:

16 = (1/2) (4)( 3 + b2)    =>         (as (1/2)4 = 2) )

16 = 2 ( 3 + b2)             =>         (divide both sides by 2)

8 = (3 + b2)                   =>         (subtract 3 from both sides)

8-3  = b2                       =>

5     =  b2


Check Area formula:

Does A = 16 = (1/2)(4)(3+5)   ?

Does 16 = (1/2) (4)(8)             ?

Does 16 = (1/2)(32)                ?  Yes it does so our calculation for b2 is correct




Thank you,

MrB

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