Name the plane that contains the points X,K,H. Enter your answer in the comments please...
1 answer:
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Answer:
Check the ecplanation
Step-by-step explanation:
A set of three vectors in represents a matrix of 3 column vectors, and each vector containing 4 entries (that is, a matrix of 4 rows, and 3 columns).
Let A be that 4x 3 matrix. The columns of A span . if and only if A has a pivot position in each row. So, there are at most 3 pivot positions in the matrix A, but the number of rows is 4, therefore, there exist at least one row not having a pivot position. If A does not have a pivot position in at least one row, then the columns of A do not span
. It implies that the set of 3 vectors of A does not span all of
.
In general, the set of n vectors in represents a matrix of in rows, and n columns (an in x matrix). So, there are at most n pivot positions in the matrix A, but n is less than the number of rows. In therefore, there exist at least one row that does not contain a pivot position.
And, hence the set of n vectors of A does not span all of . for n < m
Answer:
The point at which center of the image circle located is (-2, -3) so second option is correct.
Step-by-step explanation:
Given equation of circle is:
(i)
The general equation of circle is mentioned below,
(ii)
Here 'r' represents the radius of the circle and (h,k) shown the center of the circle.
By comparing equation (i) and equation (ii), we get
r^2 = 9
r = 3
So the center of given circle is (h,k) = (3,-4)
Also, the circle is translated 5 units left, that is towards the -x-axis. Therefore h = 3 - 5 = -2
Also, the circle is translated 1 unit up, that is towards the +y-axis. Therefore k = -4 + 1 = -3
Hence, the point at which center of the image circle located is (-2, -3) so second option is correct.