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monitta
3 years ago
7

A track team has 4 runners on a relay team. If by coincidence each runner takes an average of 45.48 seconds to complete her leg

of the relay, what is the total time to run the relay?
Mathematics
1 answer:
musickatia [10]3 years ago
6 0

Answer:

181.92 seconds

Step-by-step explanation:

We are given that,

Time taken by each person in the team = 45.48 seconds

Number of members in the team = 4

It is required to find the total time taken by the team to finish the race.

Thus, the time taken taken = 4 × 45.48 = 181.92 seconds

Hence. the team finished the race in 72.4 seconds.

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If rectangle ABCD is rotated counter clock wise 90º about the origin, what will be the coordinates of the vertex D'?
7nadin3 [17]
So, the best way to do this is translate it to clockwise. 90 degrees counterclockwise is equal to 270 degrees clockwise. So, basically, to rotate, you would follow the following format for each point-
(X,Y) -> (-Y,X)
Now, you do it for each of the points.
A= (-5,5), so A' would be (-5,-5)
B= (-1,5), so B' would be (-5,-1)
C= (-5,4), so C' would be (-4,-5)
D= (-1,4) so D' would be (-4,-1)
Notice, how all the points end up in the square below it. Each quadrant has a specific number. The top right is quadrant 1, the top left is quadrant 2, the bottom left is quadrant 3, and the bottom right is quadrant 4. If you are rotating 270 degrees clockwise, you move to the right, like a clock. That puts the new rectangle in quadrant 3. That is a way to check your work.
Now, just so you know for future reference, the following are also different formats for different problems--
A 90 degree Clockwise rotation about the origin will be (X,Y) -> (Y, -X) *Note, -x just stands for the opposite. Say your original x is a negative number. Then the prime (new) x will be positive.
A 180 degree Clockwise rotation about the origin would be (X,Y) -> (-X,-Y) *Note, -y also stands for the opposite.
A 270 degree clockwise rotation about the origin would be (X,Y) -> (-Y,X).
For translating---
90 degrees Clockwise = 270 degrees Counter
270 degrees Clockwise = 90 degrees Counter

Hope this helped!
4 0
3 years ago
Abby used the quadratic formula to find the zeros of the
MArishka [77]

Step 2: She did not simplify under the square root correctly

under the square root:

(-6)^2 =36

and -4(5)(-8) =160

therefore under the square root it needs to be square root of 36+160 which is square root of 196.

That answer is 14 when square rooted

5 0
2 years ago
Read 2 more answers
for the given kite find the length of side LM write your answer in simplest radical form. show all work.
Gnesinka [82]

Answer:

13sqrt(2) units

Step-by-step explanation:

LM² = 7² + 17²

LM² = 338

LM = sqrt(338)

LM = 13sqrt(2)

sqrt: square root

3 0
3 years ago
100 Points
UNO [17]
<span>1) Write the equation in slope intercept form if 

Slope=3/5 and intercept is 2
y = mx + b
m = 3/5 and b = 2
so

</span><span>equation in slope intercept 
</span><span>y = 3/5(x) + 2

</span><span>2. Find the x intercept of the line 5x-2y=10

x intercept when y = 0
so
</span>5x-2y=10
5x-2(0)=10
5x = 10
  x = 2

answer
x intercept (2 , 0)

hope it helps
6 0
3 years ago
Read 2 more answers
A sequence is defined recursively by the following rules: f(1)=3f(n+1)=2⋅f(n)−1 Which of the following statements is true about
Radda [10]

Answer:

f(2)=5

f(5)=33

Step-by-step explanation:

The given formula, that recursively defines the sequence is

f(1) = 3 \\ f(n + 1) = 2f(n) - 1

When n=1, we obtain;

f(1+ 1) = 2f(1) - 1 \\ f(2) = 2 \times 3 - 1 \\ f(2) = 6 - 1 \\ f(2) = 5

When n=2, we get:

f(2+ 1) = 2f(2) - 1 \\ f(3) = 2 \times 5 - 1 \\ f(3) = 10 - 1 \\ f(3) = 9

When n=3,

f(3 + 1) = 2f(3) - 1 \\ f(4) = 2f(3) - 1 \\ f(4) = 2 \times 9 - 1 \\ f(4) = 18 - 1 \\ f(4) = 17

When n=4

f(4 + 1) = 2 f(4) - 1 \\ f(5) = 2 \times 17 - 1 \\ f(5) = 34 - 1 \\ f(5) = 33

When n=5,

f(6) = 65

4 0
3 years ago
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