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Sergeeva-Olga [200]
2 years ago
12

a rectangular prism with a volume of 3 cubic units is filled with cubes with side lengths of 1/4 unit.how many 1/4 unit cubes do

es it take to fill the prism
Mathematics
1 answer:
Anvisha [2.4K]2 years ago
8 0

Answer:

12

Step-by-step explanation:

3 divided by 1/4 = 3 x 4 = 12

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Find the value of x in the following parallelogram x =
iVinArrow [24]

Answer:

x=60\degree

Step-by-step explanation:

Consecutive angles of a parallelogram are are supplementay.

\implies \: x  + 2x  = 180 \degree \\  \\ \implies \: 3x  = 180 \degree \\  \\ \implies \: x  = \frac{ 180 \degree }{3} \\  \\ \implies \: x  =60 \degree

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Are the following ratios equivalent 4:8 and 36:72
astraxan [27]

4 : 8

x 9 => 36 : 72  <=== equivalent

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3 years ago
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What is the answer to : 1.3(4.9 + 6k)
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3 years ago
when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.
sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = a^2

6 is subtracted from the square of a number = a^2 - 6

5 times the number = 5 \times a

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation ax^2 + bx + c = 0 where a \neq 0

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here in this problem,

a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6

Substituting the values in above quadratic formula, we get

\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}

We have two solutions for "a"

\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}

<h3>a = 6 or a = -1</h3>

We have asked negative solution. So a = -1

Thus the negative solution is -1

6 0
3 years ago
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