Question

A projectile is shot vertically from the ground level. It’s height h, in feet, after t seconds is given by h = 88t - 16t ^2. How long will it take the projectile to hit the ground ?

Answer 1

Answer:

it will take 5.5 seconds to hit the ground

Step-by-step explanation:

A projectile is shot vertically from the ground level. It’s height h, in feet, after t seconds is given by $h = 88t - 16t ^2$

When the projectile hits the ground then the height becomes 0

$h = 88t - 16t ^2$

$0 = 88t - 16t ^2$

GCF is -8t

$0 = 8t(11 - 2t)$

now set each factor =0 and solve for t

$8t=0, t=0$

$11-2t=0, t=\frac{11}{2}$

So it will take 5.5 seconds to hit the ground

Answer 2

Answer:

5.5 seconds.

Step-by-step explanation:

The given function is

$h = 88t - 16t ^2$

where, h is height (in feet) of projectile after t seconds.

We need to find the time taken by projectile to hit the ground.

At ground level, the height of projectile is 0.

Substitute h=0 in the given function to find the time at which it hit the ground.

$0=88t - 16t ^2$

$0=8t(11 - 2t)$

Using zero product property we get

$8t=0\Rightarrow t=0$

$11-2t=0\Rightarrow t=\frac{11}{2}=5.5$

It mean projectile hits the ground at x=0 and x=5.5 seconds. We know that x=0 is the initial stage.

Therefore, so time taken by projectile to hit the ground is 5.5 seconds.