Complete the square to make a perfect square trinomial. Then, write the result as a binomial squared. n^2+5/2n

Is the point (1,5) a solution to the equation below?

allochka39001 [22]

Answer:

A. No

Step-by-step explanation:

y = 2x + 4

(5) = 2(1) + 4

5 = 2 + 4

5 = 6 (false statement)

7 0

3 years ago

What is the answer to this mathematics expression? 12(x-2)-8x+3=

Serggg [28]

Answer:

Step-by-step explanation:

$12(x-2)-8x+3\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\=(12)(x)+(12)(-2)-8x+3\\\\=12x-24-8x+3\qquad\text{combine like terms}\\\\=(12x-8x)+(-24+3)\\\\=4x-21$

6 0

4 years ago

johnathan class has 30 boys of the students in his class 60% are girls how many girls are in johnathans class

Gekata [30.6K]

Answer:

45 girls

Step-by-step explanation:

If 60% of the class is girls then 40% of the class is boys.

30 boys are in the class, meaning that 40% of the class comprises those 30 boys

First, we need the total number of class members: 30/x = 40/100 -> 40x=3000 -> x=3000/40 -> x=75

Now that we know the total class members, at 75, we can calculate the number of girls in the class. You can do this:

0.6*75=45

or

60/100=x/75 and solve for x

5 0

4 years ago

A paper reported that in a representative sample of 282 American teens age 16 to 17, there were 71 who indicated that they had s

elena-s [515]

Answer:

$z=\frac{0.252 -0.25}{\sqrt{\frac{0.25(1-0.25)}{282}}}=0.0776$

$p_v =P(z>0.0776)=0.4691$

Since the p value is higher than the significance level so then we can conclude that we have enough evidence to FAIL to reject the null hypothesis and there is no evidence in order to say that the true proportion of teens more than a quarter of Americans age 16 to 17 have sent a text message while driving is higher than 0.25

Step-by-step explanation:

Information provided

n=282 represent the sample selected

X=71 represent the teens indicated that they had sent a text message while driving

$\hat p=\frac{71}{282}=0.252$ estimated proportion of teens indicated that they had sent a text message while driving

$p_o=0.25$ is the value that we want to test

$\alpha=0.01$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to check if more than a quarter of Americans age 16 to 17 have sent a text message while driving, and the hypothesis are:

Null hypothesis: $p\leq 0.7$

Alternative hypothesis: $p > 0.25$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing we got:

$z=\frac{0.252 -0.25}{\sqrt{\frac{0.25(1-0.25)}{282}}}=0.0776$

Decision

The p value for this case is:

$p_v =P(z>0.0776)=0.4691$

Since the p value is higher than the significance level so then we can conclude that we have enough evidence to FAIL to reject the null hypothesis and there is no evidence in order to say that the true proportion of teens more than a quarter of Americans age 16 to 17 have sent a text message while driving is higher than 0.25

8 0

4 years ago

Simply expression 1+5v+v

emmasim [6.3K]

Answer:

1 + 6v

Step-by-step explanation:

1+5v+v

Combine like terms

1 + 6v

5 0

4 years ago

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