Question

(x^(2))/(9)+(y^(2))/(49)=1 The distance from the center to the major intercept is

Answer 1

Answer:

b = 7 units.

Step-by-step explanation:

The given equation of the ellipse is

$\frac{x^{2} }{9} +\frac{y^{2} }{49}=1$

As we know in an ellipse  $\frac{x^{2} }{a^{2} }+ \frac{y^{2} }{b^{2}}=1$

a will be major axis and b is the minor axis when ( a > b )

In the given equation 49 > 9 ⇒ b² > a²

so major axis will be = √49

                                  = 7

Therefore, distance from center to the major intercept is b = 7 units.

Answer 2

Answer:

7

Step-by-step explanation:

This is an equation of an ellipse of the form:

$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$

Where a and b are the minor and major intercepts, given a<b

In this question, a<b and a = 3 and b = 7

The distance from the center to the major intercept is b, thus the distance we are seeking for is 7