Answer:
How to solve your problem
(2+6−3)+(2−10)
(x2+6x−3)+(2x−10)(x^{2}+6x-3)+(2x-10)(x2+6x−3)+(2x−10)
Simplify
1
Eliminate redundant parentheses
(2+6−3)+(2−10)
(x2+6x−3)+(2x−10)(x^{2}+6x-3)+(2x-10)(x2+6x−3)+(2x−10)
2+6−3+2−10
x2+6x−3+2x−10x^{2}+6x-3+2x-10x2+6x−3+2x−10
2
Subtract the numbers
2+6−3+2−10
x2+6x−3+2x−10x^{2}+6x{\color{#c92786}{-3}}+2x{\color{#c92786}{-10}}x2+6x−3+2x−10
2+6−13+2
x2+6x−13+2xx^{2}+6x{\color{#c92786}{-13}}+2xx2+6x−13+2x
3
Combine like terms
2+6−13+2
x2+6x−13+2xx^{2}+{\color{#c92786}{6x}}-13+{\color{#c92786}{2x}}x2+6x−13+2x
2+8−13
x2+8x−13x^{2}+{\color{#c92786}{8x}}-13x2+8x−13
Solution
2+8−13
Step-by-step explanation:
