Question

HELP ME PLEASE,

Answer 1

Answer:

b.

$( {x}^{2} + 6x - 3) + (2x - 10) \\ {x}^{2} + 8x - 13$

Answer 2

Answer:

How to solve your problem

(2+6−3)+(2−10)

(x2+6x−3)+(2x−10)(x^{2}+6x-3)+(2x-10)(x2+6x−3)+(2x−10)

Simplify

1

Eliminate redundant parentheses

(2+6−3)+(2−10)

(x2+6x−3)+(2x−10)(x^{2}+6x-3)+(2x-10)(x2+6x−3)+(2x−10)

2+6−3+2−10

x2+6x−3+2x−10x^{2}+6x-3+2x-10x2+6x−3+2x−10

2

Subtract the numbers

2+6−3+2−10

x2+6x−3+2x−10x^{2}+6x{\color{#c92786}{-3}}+2x{\color{#c92786}{-10}}x2+6x−3+2x−10

2+6−13+2

x2+6x−13+2xx^{2}+6x{\color{#c92786}{-13}}+2xx2+6x−13+2x

3

Combine like terms

2+6−13+2

x2+6x−13+2xx^{2}+{\color{#c92786}{6x}}-13+{\color{#c92786}{2x}}x2+6x−13+2x

2+8−13

x2+8x−13x^{2}+{\color{#c92786}{8x}}-13x2+8x−13

Solution

2+8−13

Step-by-step explanation: