Many insects, fish, and mammals release certain chemical messengers to signal reproductive readiness. What are these messengers
1 answer:
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Answer:
1. 1/2
2. 1/2
3. 1/4
Explanation:
Let the allele for freckles be A or a while that of dimples be B or b.
A person without freckles but heterozygous for dimples = aaBb
A person who has freckles (whose mother has no freckles) but no dimples = Aabb
aaBb x Aabb
Offspring
4 AaBb - freckled and dimpled
4 Aabb - freckled and non dimpled
4 aaBb - non freckled and dimpled
4 aabb - non freckled and non dimpled
1. <em>Probability that the parents will have a dimpled child</em> = 8/16 or 1/2
2. <em>Probability that they will have a child with freckles</em> = 8/16 or 1/2
3. <em>Probability that they will have a child with freckles and dimples</em> = 4/16 or 1/4
<u>See the attached image for the Punnet's square analysis of the cross</u>
Answer:
q = 0.42
Explanation:
This question is an example of Hardy-Weinberg question and there are two equations necessary to carry out this question;
p + q = 1
p² + 2pq + q² = 1
where;
p = the frequency of the dominant allele
q = the frequency of the recessive allele
p² = the frequency of individuals with homozygous dominant genotype
2pq = the frequency of individuals with heterozygous genotype
q² = frequency of individuals with the homozygous recessive genotype
Since the total population = 425
q² =
=
q² = 0.1765
To find q; we need to square root both side to eliminate the square from q².
∴
q = 0.4201
q = 0.42 (to two decimal places)