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svetlana [45]
3 years ago
11

Tall pea plants are dominant over short pea plants. If there are 200 short plants in the F2 generation from a cross that followe

d Mendel's methods, about how many plants will be tall in that generation?
Biology
2 answers:
nydimaria [60]3 years ago
7 0

Answer:When two true breeding plants breed they produce an F1 generation. The genotype for the true breeding parents would be TT and tt. Each of the offspring in the F1 generation would have the genotype of Tt and would have the phenotype of being tall, since tall is dominant. Next, we breed the plants of the F1 generation to produce the F2 generation. We know that the phenotype of the parents are both Tt. From this you can create a punnet square:

     T        t

T    TT     Tt

t     Tt       tt

Explanation:TT is expressed as tall

Tt is expressed as tall 

tt is expressed as short

The punnet square shows you that 75% would be tall and 25% would be short.

The 200 short plants in the questions would be 25% of 800. Take the 200 away from 800 and you get approximately 600 that would be tall.

oee [108]3 years ago
6 0

Answer:

600 tall plants.

Explanation:

Tall pea plants is dominant over short pea plants. The short pea plants has genotype tt. Tall pea plants can genotype either TT or Tt.

According to mendel's cross the cross between TT × tt will result in the following genotype.

T    TT     Tt

t     Tt       tt

The cross clearly indicates that 25% plant will be short and 75% plant will be tall. 25% plant is short out of 800. So, the remaining 600 plants will be tall.

Thus, 600 plants will be tall in the generation.

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