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Westkost [7]
3 years ago
11

How can the additive inverse be used to evaluate the problem below? –3 – (–6)

Mathematics
2 answers:
Darina [25.2K]3 years ago
5 0

Answer:

Answer is 3

Step-by-step explanation:

For the set of all real numbers we find that additive identity is 0 such that

x+0 = 0+x =x for all x in R

and inverse of x is -x for all x in R

Using this here we want to subtract -6 from -3

Instead of subtracting -3 we can add 3 the additive inverse of -3

Hence

-3 - (-6)=-3+6\\=+3

grigory [225]3 years ago
3 0
Additive inverse means adding the inverse is same as subtracting the other (???)


-3-(-6)=-3+6=3


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Find 3 ordered pairs which are Solutions to the equation 2x - 3y = 12
KonstantinChe [14]
2x-3(0)=12
2x=12
x=6
(6,0)

2(0)-3y=12
-3y=12
y=-4
(0,-4)

2x-3(2)=12
2x-6=12
2x=18
x=9
(9,2)

ANSWERS: (6,0) (0,-4) (9,2)
7 0
4 years ago
If she wants to track to have a circumference of 150 feet , what does the radius of the track need to be?
Gemiola [76]

Solution:

we are given that

she wants to track to have a circumference of 150 feet.

we have been asked to find

what does the radius of the track need to be?

As we know that

Circumference=2\pi r

Substitute the values we get

150=2 \pi r\\
\\
r=\frac{75}{\pi} \\
\\
r=\frac{75}{22/7}\\
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r=\frac{75*7}{22}=  23.863feet

Hence radius=23.863 feet.

6 0
3 years ago
Drag the simplified value into the box to mach each expression
SpyIntel [72]
<span>(4^0)+2x3-2=
1+6-2 = 5

2^2+(10-3)x2= 
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3 0
4 years ago
Due very soon! Please help
Ksju [112]

Answer:

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Consider this sequence:
zlopas [31]

nth term is: a_n=6n-2

122 is not in the sequence

Further explanation:

First of all we have to decide whether it an arithmetic sequence or geometric sequence,

Here

a_1=4\\a_2=10\\a_3=16\\a_4=22\\d=a_2-a_1\\=10-4\\= 6

a_3-a_2=16-10=6

As the common difference is same for all consecutive terms, the sequence is an arithmetic sequence

The formula for arithmetic sequence is given by:

a_n=a_1+(n-1)d

Here a_n is the nth term

a1 is the first term

n is the term number and

d is the common difference

Putting the value of a1=4 and d=6 in the formula

a_n=4+(n-1)(6)\\a_n=4+6n-6\\=6n-2

To check whether 122 will be number in the sequence or not,

Putting the value in nth term we will find the value of n, if n is an integer then 122 is a part of the sequence, otherwise not

So,

122=6n-2\\Adding\ 2\ on\ both\ sides\\122+2=6n-2+2\\124=6n\\Dividing\ both\ sides\ by\ 6\\\frac{6n}{6}=\frac{124}{6}\\n=20.6666

As the value of n is in decimal, that means none of the terms in the sequence is 122.

So,

nth term is: a_n=6n-2

122 is not in the sequence

Keywords: Arithmetic sequence, Common Difference

Learn more about arithmetic sequence at:

  • brainly.com/question/13219835
  • brainly.com/question/1836777

#LearnwithBrainly

5 0
3 years ago
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