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Westkost [7]
3 years ago
11

How can the additive inverse be used to evaluate the problem below? –3 – (–6)

Mathematics
2 answers:
Darina [25.2K]3 years ago
5 0

Answer:

Answer is 3

Step-by-step explanation:

For the set of all real numbers we find that additive identity is 0 such that

x+0 = 0+x =x for all x in R

and inverse of x is -x for all x in R

Using this here we want to subtract -6 from -3

Instead of subtracting -3 we can add 3 the additive inverse of -3

Hence

-3 - (-6)=-3+6\\=+3

grigory [225]3 years ago
3 0
Additive inverse means adding the inverse is same as subtracting the other (???)


-3-(-6)=-3+6=3


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Find the area of the trapezoid below to the nearest tenth.
kondor19780726 [428]

Answer:

Area of trapezoid = 67.6 square units

Step-by-step explanation:

Area of a trapezoid is given by the expression,

Area of the trapezoid = \frac{1}{2}(b_1+b_2)h

Here, b_1 and b_2 are the parallel sides of the given trapezoid.

And 'h' = Height between the parallel sides

From the given triangle ABE,

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m(∠ABE) = 120° - 90°

               = 30°

By applying cosine rule in the given triangle,

cos(30°) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

\frac{\sqrt{3} }{2}=\frac{BE}{AB}

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By applying sine rule in ΔABE,

sin(30°) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

\frac{1}{2}=\frac{AE}{AB}

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Length of b_2=AD=(AE+EF+FD) [AE = FD, since given trapezoid ABCD is an isosceles trapezoid]

                b_2=3+10+3

                b_2=16

Height between the parallel sides h=3\sqrt{3}

Area of the trapezoid = \frac{1}{2}(BC+AD)BE

                                    = \frac{1}{2}(10+16)(3\sqrt{3})

                                    = 39\sqrt{3}

                                    = 67.6 square units

8 0
3 years ago
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Answer:

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Step-by-step explanation:

First we have to figure out what is 6.6% of 160.

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Now we just add 160 with the 6.6% to figure out the answer.

160 + 10.56 = 170.56

So, the answer is 170.56 dollars.

Hope this helps! :)

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