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MrRa [10]
4 years ago
4

How are the graphs of the functions f(x) = StartRoot 16 EndRoot Superscript x and g(x) = RootIndex 3 StartRoot 64 EndRoot Supers

cript xrelated? The functions f(x) and g(x) are equivalent. The function g(x) increases at a faster rate. The function g(x) has a greater initial value. The function g(x) decreases at a faster rate.

Mathematics
2 answers:
swat324 years ago
5 0

Answer:

The function g(x) increases at a faster rate

The function g(x) has a greater initial value

Step-by-step explanation:

we have

f(x)=(\sqrt{16})^{x}

g(x)=3(\sqrt{64})^{x}

we know that

16=4^{2}

substitute in f(x)

f(x)=(\sqrt{4^{2}})^{x}=4^x

64=8^{2}

substitute in g(x)

g(x)=3(\sqrt{8^{2}})^{x}=3(8)^x

<em>Compare the functions</em>

f(x) and g(x) are not equivalent

<em>Find the initial value</em>

For x=0

f(0)=4^0=1

g(0)=3(8)^0=3

The initial value of g(x) is greater than the initial value of f(x)

using a graphing tool

The function g(x) increases at a faster rate than the function f(x) (see the attached figure)

That means ----> The value of g(x) is greater than the value of f(x) for the same value of x

therefore

The function g(x) increases at a faster rate

The function g(x) has a greater initial value

Finger [1]4 years ago
5 0

Answer:

The functions f(x) and g(x) are equivalent.

Step-by-step explanation:

option a

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