All categories

3 years ago

Which of the following are examples of a function? Justify your answers.

Mathematics

1 answer:

stiv31 [10]3 years ago

7 0

Answer: Hello there!

The relation of two quantities is a function only when for each point in the domain, there is only one point associated on the codomain (or range).

this means that, for a point x in the domain; if f(x) = y1 and f(x) = y2, this means that y1 = y2.

now we have:

"The assignment of each rational number to the product of its numerator and denominator."

here you are "assigning" rational numbers, to the product of their parts, then the rational numbers are the range, and the domain is the product of two integer numbers, so the domain is the set of all integer numbers.

now suppose we have the numer 6, and we know that 6 = 2*3, then:

f(6) = 2/3 or f(6) = 3/2

so we can asociate the numer 6 in the domain, with two numbers in the codomain, so this relation is not a function.

You might be interested in

Write the ratio as a fraction in simplest form,with whole numbers in the numerator and denominator 42 to 6

nadya68 [22]

42/6 simplified equals 7/1 or just 7

4 0

3 years ago

The zeros of a quadratic function are 6 and -4. Which of these choices could be the function?

geniusboy [140]

Answer:

Step-by-step explanation:

If x = a is a zero of f(x) then (x - a) is a factor of f(x)

Here the zeros are x = 6 and x = - 4 then the corresponding factors are

(x - 6) and (x - (- 4) ) , that is (x - 6) and (x + 4)

Then f(x) is the product of the factors

f(x) = a(x - 6)(x + 4) ( a is a multiplier )

If a = 1 , then

f(x) = (x - 6)(x + 4) ← is a possible choice → C

6 0

3 years ago

Read 2 more answers

A 5×12 rectangle is inscribed in a circle. What is the radius of the circle need help with this

Tamiku [17]

Answer:

6.5

Step-by-step explanation:

Im not 100% sure because I may have overcomplicated this but im going to submit this anyway.

4 0

3 years ago

No files please! thanks

BigorU [14]

Answer:

y = $-\frac{1}{3}$

$2\frac{2}{3}=x$

Step-by-step explanation:

To solve a system of equations, solve one or both of the equations for the same variable. Then multiply one of the equations such that the coefficients of one variable are the additive inverse of the variable in the other equation. After doing so, add the two equations, then solve for the other variable using inverse operations. Finally, substitute the value of the other variable into one of the original equations in the system and solve for the unknown variable.

2x + y = 3

y = x - 2

First, manipulate the first equation such that the equation is solved for (y), this can be done using inverse operations,

y = 3 - 2x

y = x - 2

Now multiply the second equation by (2) so that the (x) coefficients are additive inverses of each other,

y = 3 - 2x

2y = 2x - 4

Add the equations,

3y = -1

Inverse operations,

3y = -1

/3 /3

y = $-\frac{1}{3}$

Now back solve, substitute the value of (y) into the equation and solve for (x),

$y=x-3\\$

Substitute,

$(-\frac{1}{3})=x-3$

$2\frac{2}{3}=x$

5 0

3 years ago

How do i write 720,080 in expanded form with exponents

max2010maxim [7]

In exponential form 720,080 is: 7 × 10^5 + 2 × 10^4 + 0 × 10^3 + 0 × 10^2 + 8 × 10^1 + 0 × 10^0

4 0

3 years ago