Surface area of cylinder is 2 (pi)rh+2(pi)r^2
this is the area of the side [(2 (pi)rh] and the two circles together [2 (pi)r^2]
122. r=24
h=15
2 (3.14)24×15+2 (3.14)24^2
6.28×24×15+6.28×24^2
2260.8+3617.28
5878.08mm
123. r=5
h=8
2 (3.14)5×8+2 (3.14)5^2
6.28×5×8+6.28×5^2
251.2+157
408.2cm
124. the surface area of a cylinder that has a hole is going to be
surface area of big cylinder-2small area circles (the holes) + the area of the holes sides
hopefully that isn't too confusing
big radius: 8
height: 14
little radius: 2.5
height: 14
2 (3.14)8×14+2 (3.14)8^2
6.28×8×14+6.28×8^2
703.36+401.92
1105.28in (area of big cylinder)
2 (3.14)2.5^2 (two small holes)
6.28×2.5^2
39.25in (area of holes)
2 (3.14)×2.5×14 (area of side)
6.28×2.5×14
219.8in
1105.28-39.25+219.8
1066.03+219.8
1285.83in total surface area
125. h=20
r=6 since diameter is a foot or 12 in, half of that is 6
2 (3.14)6×20+2 (3.14)6^2
6.28×6×20+6.28×6^2
753.6+226.08
979.68in
126. first radius= 10
first height = 6
second radius= 6
second height= 10
2 (3.14)10×6+2 (3.14)10^2
6.28×10×6+6.28×10^2
376.8+628
1004.8in (surface area of first cylinder)
2 (3.14)6×10+2 (3.14)6^2
6.28×6×10+6.28×6^2
376.8+226.08
602.88in (surface area of second cylinder)
1004.8-602.88= 401.92
the surface area of the cylinder with radius 10 and height 6 is GREATER that the surface area of the cylinder with radius 6 and height 10..
by 401.92in
So, we have the points. Here are the graphs:
So, the answer is d
Experimental probability = number of positive results / number of experiments
Experimental probability = 67 / 450
Answer: 13.2300 is the next guess
To use the Babylonian method, you first start with your guess of 13.0463. Then, you add to it the original number divided by 13.0463.
It would look like this:
13.0463 + 175/13.0463 =26.460006
Then, you divide this number by 2.
The result is 13.2300
This value is closer to the correct square root of 175.
