What is the perimeter of a square with sides of 17ft

Mathematics

2 answers:

Fittoniya [83]2 years ago

8 0

Answer:

Step-by-step explanation:

Since its a square, it has 4 sides right?

If each side is 17ft, you can either add 17 four times, or, you can multiply 17 by four.

Which would give you 68.

The perimeter is 68ft

Elodia [21]2 years ago

6 0

68 ft. 17 times 4 sides = perimeter.

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Write tan in terms of sin and cos.

$\displaystyle \lim_{t\to0}\frac{\tan(6t)}{\sin(2t)} = \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)}$

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$\displaystyle \lim_{x\to0}\frac{\sin(x)}x = 1$

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$\displaystyle \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)} = \lim_{t\to0} \frac{\sin(6t)}{6t} \times \frac{2t}{\sin(2t)} \times \frac{6t}{2t\cos(6t)} \\\\ = \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right)$

Then using the known limit above, it follows that

$\displaystyle \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right) = 1 \times 1 \times \frac3{\cos(0)} = \boxed{3}$