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Firlakuza [10]
3 years ago
15

A rectangular sandbox has a width that's 1⁄4 of its length. The total area of the sandbox is 36 square feet. Find the dimensions

of the sandbox
Mathematics
1 answer:
lutik1710 [3]3 years ago
6 0

Answer:

Dimensions of box

Length is 12 feet

Width is 3 feet

Step-by-step explanation:

Let's assume length of sandbox is L

width of box is W

we are given

A rectangular sandbox has a width that's 1⁄4 of its length

so, we can write as

W=\frac{1}{4}L

we know that

area = length*width

so, we get

A=L\times W

now, we can plug back W

A=L\times \frac{1}{4}L

we can set Area=36

36=L\times \frac{1}{4}L

now, we can solve for L

L^2=144

L=12

now, we can find W

W=\frac{1}{4}\times 12

W=3

So, dimensions of box

Length is 12 feet

Width is 3 feet

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Your club has been asked to contribute to a service project benefiting a local charitable organization. You plan to buy a combin
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Answer:

the possible combinations of $5 and $10 gift cards your club can purchase are :

eight $5 gift cards and twelve $10 gift cards

nine $5 gift cards and eleven $10 gift cards

or ten each of $5 gift cards and $10 gift cards

Step-by-step explanation:

From the information given:

You plan to buy a combination of $5 and $10 gift cards

You plan to buy exactly 20 gift cards and want to spend between $150 and $160.

The objective is to determine the possible combinations of $5 and $10 gift cards your club can purchase?

Let assume the g is the number of the $5 gift cards bought;

then (20 - g) will be the number of the $10 gift card bought.

Thus; the compound inequality for the amount spent between $150 and $160 will be:

= 150 ≤ 5g + 10(20 - g) ≤ 160

=  150 ≤ 5g + 200 - 10g ≤ 160

= 150 ≤ 5g -10 g + 200 ≤ 160

= 150 ≤ -5g + 200 ≤ 160

= 150-200 ≤ -5g ≤ 160 -200

= -50  ≤ -5g ≤ -40

Divide through by -5

= 10 ≥ g ≥ 8

= 8 ≤ g ≤ 10

Thus; the possible combinations of $5 and $10 gift cards your club can purchase are :

eight $5 gift cards and twelve $10 gift cards  = i.e 8 ×$5 + 12 ×$10

= $40+$120

=$160

 

nine $5 gift cards and eleven $10 gift cards

 =  9 ×$5 + 11 ×$10

= $45 + $110

= $155

or ten each of $5 gift cards and $10 gift cards

=  10 ×$5 + 10 ×$10

= $50 + $100

= $150

These combinations falls in between the range of $150 and $160.

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dlinn [17]

Answer with Step-by-step explanation:

Let P(n)=1^2+2^2+3^2+.....+n^2=\frac{n(n+1)(2n+1)}{6}

Substitute n=2

Then  P(2)=1+2^2=5

P(2)=\frac{2(2+1)(4+1)}{6}=5

Hence, P(n) is true for n=2

Suppose that P(n) is true for n=k >1

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Now, we shall prove that p(n) is true for n=k+1

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Substitute the value of P(k)

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P(k+1)=(k+1)(\frac{k(2k+1}{6})+k+1)

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P(k+1)=(k+1)(\frac{2k^2+4k+3k+6}{6})

P(k+1)=\frac{(k+1)(k+2)(2k+3)}{6}

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