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LenKa [72]
2 years ago
5

F ( x ) = 3 x − 12 f(x)= 3x−12 ​

Mathematics
1 answer:
Nina [5.8K]2 years ago
8 0

The inverse of the given function 3x - 12 is determined as f⁻¹(x) = x/3 + 4.

<h3>What is inverse of a function?</h3>

An inverse of a function is a function that serves to replace another function.

That is, if f(x) produces y, then putting y into the inverse of f produces the 0ut-put x .

Thus, an inverse function or an anti function is defined as a function, which can reverse into another function.

The inverse of the given function; f(x)= 3x − 12 is calculated as follows;

y = 3x - 12

replace y with x and x with y as shown below;

x = 3y - 12

now, solve for y

x + 12 = 3y

divide both sides of the equation by 3

x/3 + 12/3 = 3y/3

x/3 + 4 = y

f⁻¹(x) = x/3 + 4

Thus, the inverse of the given function 3x - 12 is determined as f⁻¹(x) = x/3 + 4.

Learn  more about inverse of a function here: brainly.com/question/3831584

#SPJ1

The complete question is written below:

find the inverse of the function, f(x) = 3x - 12

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Answer: hello your question is poorly written attached below is the complete question

answer:

\sqrt{3}(cos(\frac{3\pi }{2}) + isin(\frac{3\pi }{2})) --- ( option d )

Step-by-step explanation:

The correct option that represents a  square root of 3 as related to the question attached below is :

\sqrt{3}(cos(\frac{3\pi }{2}) + isin(\frac{3\pi }{2}))

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Answer:

0.4,3/5,5/8,74%

Step-by-step explanation:

Change them all into decimals.

Get 0.4,0.625,0.74,0.6

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Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{8},0)(± 8 ​ ,0)(, plus minus, square root o
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The equation of ellipse centered at the origin

\frac{x^2}{18} +\frac{y^2}{10} =1

Step-by-step explanation:

given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)

The foci are (-C,0) and (C ,0)

Given data (±√8,0)  

the focus has x-coordinates so the focus is  lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so c0-vertices are (0,±√10)

given focus C = ae = √8

Given co-vertices ( minor axis) (0,±b) = (0,±√10)

b= √10

The relation between the focus and semi major axes and semi minor axes are c^2=a^2-b^2

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a^{2} = (\sqrt{8} )^{2} +(\sqrt{10} )^{2}

a^{2} =18

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The equation of ellipse formula

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

we know that a=\sqrt{18} and b=\sqrt{10}

<u>Final answer:</u>-

<u>The equation of ellipse centered at the origin</u>

<u />\frac{x^2}{18} +\frac{y^2}{10} =1<u />

                                   

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