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ki77a [65]
3 years ago
13

Is square -64 an integer,irrational,ot a rational number PLEASE HELP ME ASAP!!!

Mathematics
2 answers:
Anarel [89]3 years ago
6 0

Answer:

integer and rational

Step-by-step explanation:

-64 is an integer, which is also a rational type of number

andreyandreev [35.5K]3 years ago
5 0

Answer: integer

-64² = -4096. an integer is a number that can be written without a fraction, in this case, -64² doesn't require one

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4) The limit does not exist.

General Formulas and Concepts:

<u>Calculus</u>

Limits

  • Right-Side Limit:                                                                                             \displaystyle \lim_{x \to c^+} f(x)
  • Left-Side Limit:                                                                                               \displaystyle \lim_{x \to c^-} f(x)

Limit Rule [Variable Direct Substitution]:                                                             \displaystyle \lim_{x \to c} x = c

Step-by-step explanation:

*Note:

For a limit to exist, the right-side and left-side limits must be equal to each other.

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x ,\ x < 5\\8 ,\ x = 5\\x + 3 ,\ x > 5\end{array}

<u>Step 2: Find Left-Side Limit</u>

  1. Substitute in function [Left-Side Limit]:                                                       \displaystyle \lim_{x \to 5^-} 5 - x
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                          \displaystyle \lim_{x \to 5^-} 5 - x = 5- 5 = 0

<u>Step 2: Find Left-Side Limit</u>

  1. Substitute in function [Right-Side Limit]:                                                     \displaystyle \lim_{x \to 5^+} x + 3
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle \lim_{x \to 5^+} x + 3 = 5 + 3 = 8

∴ since  \displaystyle \lim_{x \to c^+} f(x) \neq \lim_{x \to c^-} f(x)  ,  \displaystyle  \lim_{x \to 5} f(x) = \text{DNE}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

5 0
3 years ago
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