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jonny [76]
3 years ago
5

Write a recursive formula for f(n) = -3 + 2 for n > = 1

Mathematics
1 answer:
bearhunter [10]3 years ago
5 0

Answer:

f(n) = f(n - 1) - 3

Step-by-step explanation:

Assuming the explicit formula is

f(n) =  - 3n + 2

Then f(1)=-3+2=-1

f(2)=-6+2=-4

The common difference is -4--1=-3

Then the recursive formula is given as:

f(n) = f(n - 1) + d

f(n) = f(n - 1) - 3

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Write the symbols and use to find the next terms . 3,6,9,12​
Elodia [21]

Answer:

15

Step-by-step explanation:

the pattern is adding by three so 12+3=15

8 0
3 years ago
2.3×10⁹=(1×10³)(2.3×10^n)​
kotegsom [21]

Answer:

<em>n = 6 </em>

Step-by-step explanation:

2.3 × 10^{9} = (1 × 10³)(2.3 × 10^{n} )

(1 × 10³)(2.3 × 10^{n} ) = (1)(2.3) × (10³)( 10^{n} ) = 2.3 × 10^{3+n}

2.3 × 10^{3+n} = 2.3 × 10^{9} ⇒ 3 + n = 9 ⇒ <em>n = 6</em>

5 0
3 years ago
I dont know i need help please
Minchanka [31]

Answer:

C

Step-by-step explanation:

8 0
2 years ago
Henry places £6000 in an account which pays 4.6% compound interest each year
aivan3 [116]

Answer:

£ 6,564.70

Step-by-step explanation:

Henry places £6000 in an account which pays 4.6% compound interest each year. Calculate the amount in his amount after 2 years

Compound Interest formula =

A = P(1 + r/n)^nt

A = Final Amounrt

P = Principal = £6,000

r = Interest rate = 4.6%

t = Time in years = 2 years

n = Compounding frequency = Yearly = 1

First, convert R percent to r a decimal

r = R/100

r = 4.6%/100

r = 0.046 per year,

Then, solve our equation for A

A = P(1 + r/n)^nt

A = 6,000.00(1 + 0.046/1)^(1×2)

A = £ 6,564.70

The amount in his account after 2 years = £ 6,564.70

7 0
3 years ago
FlybynightSavings.com is offering a savings account that pays 33% compounded continuously. How much interest would a deposit of
pychu [463]
The exact calculations:
Principal, P=3000
interest rate = 33% per year
Period, t=10 years

Future value
F=Pe^(it)
=3000e^(0.33*10)
=81337.92

Interest 
= future value - principal
= 81337.92-3000
= 78337.92  (to the nearest cent)


6 0
3 years ago
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