All categories

3 years ago

Write a recursive formula for f(n) = -3 + 2 for n > = 1

Mathematics

1 answer:

bearhunter [10]3 years ago

5 0

Answer:

$f(n) = f(n - 1) - 3$

Step-by-step explanation:

Assuming the explicit formula is

$f(n) = - 3n + 2$

Then f(1)=-3+2=-1

f(2)=-6+2=-4

The common difference is -4--1=-3

Then the recursive formula is given as:

$f(n) = f(n - 1) + d$

$f(n) = f(n - 1) - 3$

You might be interested in

What does 100,000 • 1,470 • 300,890 • 69 =

Mazyrski [523]

If you multiply them all you get 3.0519273e+15 as your answer.

5 0

3 years ago

Find cot theta if 180° < theta < 270° and cos theta = - sqrt 3/2

avanturin [10]

Answer:

cot theta = -√3

Step-by-step explanation:

we are given that cos theta = - √3/2 within the range 180° < theta < 270° and

since cos theta = adj/hyp

adj = - √3

hyp = 2

Get the opposite using the pythagoras theorem

hyp^2 = opp^2 + adj^2

2² = opp² + (-√3)²

4 = opp² + 3

opp² = 4-3

opp² = 1

opp = 1

tan theta = opp/adj

tan theta = - 1/√3

Recall that cot theta = 1/tan theta

cot theta = 1/(-1/√3)

cot theta = -√3

8 0

3 years ago

Y-(5-(y-x)) x = 4 y = 6<br><br> I need the steps please, this is a little bit confusing..

KATRIN_1 [288]

Answer:

Step-by-step explanation:

substitute x = 4 , y = 6 into the expression

y - (5 - (x - y))

= 6 - (5 - (6 - 4))

= 6 - (5 - 2))

= 6 - 3

= 3

3 0

2 years ago

Eric is studying people's typing habits. He surveyed 525 people and asked whether they leave one space or two spaces after a per

Otrada [13]

Answer: (0.8115, 0.8645)

Step-by-step explanation:

Let p be the proportion of people who leave one space after a period.

Given: Sample size : n= 525

Number of people responded that they leave one space. =440

i.e. sample proportion: $\hat{p}=\dfrac{440}{525}\approx0.838$

z-score for 90% confidence level : 1.645

Formula to find the confidence interval :

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$0.838\pm (1.645)\sqrt{\dfrac{0.838(1-0.838)}{525}}\\\\=0.838\pm (1.645)\sqrt{0.00025858285}\\\\=0.838\pm (1.645)(0.01608)\\\\= 0.838\pm0.0265\\\\=(0.838-0.0265,\ 0.838+0.0265)\\\\=(0.8115,\ 0.8645)$

Hence, a 90% confidence interval for the proportion of people who leave one space after a period: (0.8115, 0.8645)

3 0

3 years ago

Consider the equation:

Alenkasestr [34]

Answer:

the equation is not correct....

well, it should look sth. like (x+or- number)^2=number

5 0

3 years ago