<h2>
The area of a triangle is =54 square units</h2><h2>
The perpendicular distance from B to AC is = 
</h2>
Step-by-step explanation:
Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)
The area of a triangle is= ![\frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Bx_1%28y_2-y_3%29%20%2Bx_2%20%28y_3-%20y_1%29%2Bx_3%28y_1-y_2%29%5D)
=![|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|](https://tex.z-dn.net/?f=%7C%5Cfrac%7B1%7D%7B2%7D%20%5B2%282-8%2B12%288-1%29%2B12%281-2%29%5D%7C)
=
= 54 square units
The length of AC = 
= 
=
units
Let the perpendicular distance from B to AC be = x
According To Problem
⇔
units
Therefore the perpendicular distance from B to AC is =
This is a working backwards problem. You know he has $35 at the end. Before he gave his brother $5, he would have $40, which is half of what he had before he bought the clothes, so he would have had $80. Before he spent the $40 on shoes, he would have had $120, so the answer is $120.
Potential energy<span> is the </span>energy<span> possessed by an object because of its position.
So it is D the highest point of the trajectory. </span>
Cannot reduce, it is already in simplest form. You can convert it to a decimal though, 0.671875
