The location of the y value of R' after using the translation rule is -10
<h3>What will be the location of the y value of R' after using the translation rule? </h3>
The translation rule is given as:
(x + 4, y - 7)
The pre-image of R is located at (-17, -3)
Rewrite as
R = (-17, -3)
When the translation rule is applied, we have:
R' = (-17 + 4, -3 - 7)
Evaluate
R' = (-13, -10)
Remove the x coordinate
R'y = -10
Hence, the location of the y value of R' after using the translation rule is -10
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So your circumference would be <span>34.557519189488 cm</span>. hope that helped
Circle equation
(x - h)^2 + (y - k)^2 = r^2
Since radius isn't given use the center and point, with the distance formula, to find the radius.
D=sqrt((x2-x2)^2+)y2-y1)^2)
D=sqrt((1-0)^2+(2-6)^2
D=sqrt(1+16)
D=sqrt 17
radius = sqrt 17
(h, k) is the center and r is the radius
(x - 1)^2 + (y - 2)^2 = 17
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