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Stells [14]
3 years ago
5

A city grid of Anytown, USA is shown on the grid below. The fire department is represented by quadrilateral RSTU. Another fire d

epartment is opening in a different part of the city to maximize fire protection. The size of the new department's property must be congruent to the older department. Vertices A and B are plotted on the grid below to represent two vertices of the new fire department quadrilateral ABCD:
Map of Anytown. The line y equals 7 is Main Road. The line y equals 3 is Rose Lane. The line y equals negative 1 is Crystal Ave

What could be the ordered pairs representing vertices C and D of quadrilateral ABCD so that the new fire department is congruent to the old fire department? 


C(1, −3), D(4, −3)
C(1, −2), D(4, −2)
C(1, −4), D(4, −4)
C(1, −5), D(4, −5)
Mathematics
2 answers:
Pavlova-9 [17]3 years ago
7 0
Since the starting and original place is a 4 x 3 rectangle, and the new position already has a side length of 3. We are now going to look for the two points that make a second side of 4. So, the points C(1, -5) and D(4, -5) satisfy the requirements.
Vadim26 [7]3 years ago
3 0

C(1, -5), D(4, -5)


Hope this helped :)

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A=\cfrac{1}{4}(6)\cfrac{9^2}{2^2} \cot(30^o)\implies A=\cfrac{243}{8}\cot(30^o)\implies A=\cfrac{243\sqrt{3}}{8} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=\frac{4}{5} \end{cases}\implies A=\pi \left( \cfrac{4}{5} \right)^2\implies A=\cfrac{16\pi }{25} \\\\[-0.35em] ~\dotfill

\stackrel{\textit{area of the hexagon}}{\cfrac{243\sqrt{3}}{8}}~~ - ~~\stackrel{\textit{area of the circle}}{\cfrac{16\pi }{25}}\implies \cfrac{6075\sqrt{3}-128\pi }{200}

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