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3 years ago

The answer to (m-7)(9m-1)

1 answer:

7 0

To solve this, we will need to distribute out the values in parentheses. To do this, we can use a series called the FOIL method, where we multiply the first terms, outside terms, inside terms, and last terms.

(m-7)(9m-1)
9m²-m-63m+7
9m²-64m+7

Using the math above, we can see that when we multiply these values, the answer is 9m²-64m+7.

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Write an equation of a line that is perpendicular to the line x-2y=8

Helen [10]

2x+y=8 is the equation perpendicular to x-2y=8.

6 0

3 years ago

Read 2 more answers

Logariths, please help

Valentin [98]

Answer:

{ - 2 , 8 }

Step-by-step explanation:

$log_{4}$ ( x² - 6x ) = 2

4² = ( x² - 6x )

x² - 6x - 16 = 0

- 6 = - 8 + 2

- 16 = - 8 * 2

( x - 8 )( x + 2 ) = 0 ⇒ $x_{1}$ = - 2 , $x_{2}$ = 8

{ - 2 , 8 }

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2 years ago

Pls help me first get 10 you know

Luba_88 [7]

Option D, 63 cm

Explanation:

The scale of model is of local park is

This means that each dimension of the model is 21 times smaller than the actual park (to be developed in future)

Given -

Depth of the pond centi meter

Depth of the real pond will be 21 times of the depth of the model.

Thus , real pond's depth is equal to

Hence, option D is correct

7 0

2 years ago

A train leaves Westchester at 6:30. What time should it arrive at Middlewich

Sholpan [36]

Answer:

a). 6:51

b). 6:30 am

c). 34 minutes

Step-by-step explanation:

a). Train leaves Westchester at 6:30.

From the arrival - departure table in column (2),

Arrival time of the train at middlewich = 6:51

b). Kate has to reach Southam before 9:00 am

Therefore, time of the latest train that she can catch to get to work on time is 6:30 am

By this train she can reach at 07:19 at Southam.

c). Duration of journey from Westchester to Eastwick = 06:34 - 06:00

= 00:34

≈ 34 minutes

8 0

3 years ago

Solve the quadratic equation 3x²-3x-1=0? (by using the square method)

ohaa [14]

Answer:

x=1 and x=-1/3

Step-by-step explanation:

$3x^2-2x-1=0\\\\3(x^2-\frac{2}{3}x-\frac{1}{3})=0\\ \\3(x^2-\frac{2}{3}x-\frac{1}{3}+\frac{4}{9})=3(\frac{4}{9})\\ \\ 3(x^2-\frac{2}{3}x+\frac{1}{9})=\frac{4}{3}\\ \\ 3(x-\frac{1}{3})^2=\frac{4}{3}\\ \\(x-\frac{1}{3})^2=\frac{4}{9}\\ \\x-\frac{1}{3}=\pm\frac{2}{3}$

$x-\frac{1}{3}=\frac{2}{3}\\ \\x=\frac{3}{3}\\ \\x=1$

$x-\frac{1}{3}=-\frac{2}{3}\\ \\x=-\frac{1}{3}$

Therefore, x=1 and x=-1/3

8 0

2 years ago