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2 years ago

10

The answer to (m-7)(9m-1)

1 answer:

faust18 [17]2 years ago

7 0

To solve this, we will need to distribute out the values in parentheses. To do this, we can use a series called the FOIL method, where we multiply the first terms, outside terms, inside terms, and last terms.

(m-7)(9m-1)
9m²-m-63m+7
9m²-64m+7

Using the math above, we can see that when we multiply these values, the answer is 9m²-64m+7.

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4.20. According to a report released by the National Center for Health Statistics, 51% of U.S. households has only cell phones (

Sergeu [11.5K]

Answer:

The probability that the household has only cell phones and has high-speed Internet is 0.408

Step-by-step explanation:

Let A be the event that represents U.S. households has only cell phones

Let B be the event that represents U.S. households have high-speed Internet.

We are given that 51% of U.S. households has only cell phones

P(A)=0.51

We are given that 70% of the U.S. households have high-speed Internet.

P(B)=0.7

We are given that U.S. households having only cell phones, 80% have high-speed Internet. A U.S household is randomly selected.

P(B|A)=0.8

$\frac{P(A\capB)}{P(A)}=0.8\\P(A\capB)=0.8 \times P(A)\\P(A\capB)=0.8 \times 0.51\\P(A\capB)=0.408$

Hence the probability that the household has only cell phones and has high-speed Internet is 0.408

7 0

2 years ago

Solve the inequality if you can help i would appreciate it <br><br> n-9 < 4

saveliy_v [14]

Answer:

n<4+9

n<13

Step-by-step explanation:

5 0

2 years ago

What is the mean of -36,-25,12,-3 and 18

skad [1K]

I think the mean is -6.8

6 0

2 years ago

Find the mean of each data set. 11,16,17,20,26

Pavel [41]

Answer:

The mean is 18

Step-by-step explanation:

8 0

2 years ago

The test results for a class with 24 students are normally distributed with a mean of 82 and a standard deviation of 8.9. What i

alekssr [168]

Answer:

The value is $P( X > 80 ) = 0.58901$

Step-by-step explanation:

From the question we are told that

The sample size is n = 24

The mean is $\mu = 82$

The standard deviation is $\sigma = 8.9$

Generally the probability that a randomly chosen student earned a B or higher on the test (score of 80 or higher ) is mathematically represented as

$P( X > 80 ) = P( \frac{ X - \mu }{\sigma } > \frac{ 80 - 82 }{ 8.9 } )$

$\frac{X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ X )$

=> $P( X > 80 ) = P(Z > -0.225 )$

From the z table the area under the normal curve to the right corresponding to -0.225 is

$P(Z > -0.225 ) = 0.58901$

=> $P( X > 80 ) = 0.58901$

5 0

2 years ago