Please help me with this problem
2 answers:
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Answer:
.
Step-by-step explanation:
We have been given two sets as A: {71,73,79,83,87} B:{57,59,61,67}. We are asked to find the probability that both numbers are prime, if one number is selected at random from set A, and one number is selected at random from set B.
We can see that in set A, there is only one non-prime number that is 87 as it is divisible by 3.
So there are 4 prime number in set A and total numbers are 5.
We can see that in set B, there is only one non-prime number that is 57 as it is divisible by 3.
So there are 3 prime number in set B and total numbers are 4.
Now, we will multiply both probabilities to find the probability that both numbers are prime. We are multiplying probabilities because both events are independent.
Therefore, the probability that both numbers are prime would be .
The ingredients given are for 4 dozen cookies; however, Christian only want to make one dozen, meaning he requires only 1/4 the ingredients.
1/4 of 2 1/4 cups of while sugar is found the following way.
First, we write 2 1/4 as an improper fraction
1/4 of this is
Hence, Christian requires 9/16 cups of white sugar.
Similarly, the 1/4 of 3/4 cups of brown sugar is
Hence, Chrisitan requires 3/16 cups of brown sugar.
Therefore, the total cups of sugar required is the sum of
3/4 cups of sugar.