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AysviL [449]
3 years ago
9

Help me with these please!!

Mathematics
1 answer:
Arlecino [84]3 years ago
4 0
Let's take a look. A baker is using three cups of water for every eight ounces of water.

Let's think of a ratio!

8 * x = 96
x =  cups of flour.


Let's solve the equation.

96 divided by 8 equals 12.

The correct answer would be D - 12 cups of flour.
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HelllllllP it’s due today :/
svetlana [45]

Answer:

Rectangle

Step-by-step explanation:

Note the definition of a rectangle. All angles must be 90°, and opposite sides are parallel and congruent.

It says that Andre "drew a quadrilateral with <em>four right angles and two pairs of congruent sides</em>.", making rectangle a candidate as an answer.

~

4 0
3 years ago
Consider the graph below:
Julli [10]
It would be C) y = ( x + 1 ) ( x - 3 ) ( x - 2 ) because when you graph the points it falls to the left and rises to the right.
6 0
3 years ago
Read 2 more answers
3. If x2 + 4 = 29, then x2 - 4 = ?<br> A. 5<br> B. 121<br> C.<br> 21<br> D. 25<br> E. 33
EastWind [94]
Answer is c as x is 25/2
7 0
3 years ago
Read 2 more answers
Which relation is a function? Help please
WARRIOR [948]

Answer:

The bottom right (v shaped one) is a function

Step-by-step explanation:

Hope this helps:)

4 0
2 years ago
Read 2 more answers
Find the values of k so that each remainder is three. <br> 10. (x^2+ 5x + 7) = (x + k)
Goryan [66]

Answer:

k=1\text{ or } k=4

Step-by-step explanation:

We can use the Polynomial Remainder Theorem. It states that if we divide a polynomial P(x) by a <em>binomial</em> in the form (x - a), then our remainder will be P(a).

We are dividing:

(x^2+5x+7)\div(x+k)

So, a polynomial by a binomial factor.

Our factor is (x + k) or (x - (-k)). Using the form (x - a), our a = -k.

We want our remainder to be 3. So, P(a)=P(-k)=3.

Therefore:

(-k)^2+5(-k)+7=3

Simplify:

k^2-5k+7=3

Solve for <em>k</em>. Subtract 3 from both sides:

k^2-5k+4=0

Factor:

(k-1)(k-4)=0

Zero Product Property:

k-1=0\text{ or } k-4=0

Solve:

k=1\text{ or } k=4

So, either of the two expressions:

(x^2+5x+7)\div(x+1)\text{ or } (x^2+5x+7)\div(x+4)

Will yield 3 as the remainder.

5 0
3 years ago
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