Question

What is the value of the expression? Do not use a calculator. tan(-11pi/6)

Answer 1

Tan(-11π/6)
= tan(π/6 - 2π)
= tan(π/6)
= √(3)/3

Answer 2

Answer:

$tan(\frac{-11\pi}{6})= tan (-\pi +\frac{-5\pi}{6})\\\\ tan[-(\pi +\frac{5\pi}{6})]\\\\=-tan(\pi +\frac{5\pi}{6})\\\\=-(tan\frac{5\pi}{6})\\\\=-tan(\frac{5\pi}{6})\\\\=-tan(\pi -\frac{\pi}{6})\\\\=tan \frac{\pi}{6}\\\\ =\frac{1}{\sqrt{3}}$