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katen-ka-za [31]
3 years ago
15

What is the answer to the equation 13=1/6y + 2x

Mathematics
1 answer:
Eddi Din [679]3 years ago
6 0
13=1/6y+2x
-1/6y  -1/6y
-1/6y+13=2x
         -13 -13
-1/6y=2x-13
   *-6   *-6
y=-12x-13

*I multiply it by -6 because -6 is the reciprocal of -1/6, and I can't divide -1/6, actually I can, but it just going to be more confusing that way, and the fastest way to get rid of the -1/6 when you solving this type of equation is multiply it by its reciprocal.
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Write an equation for the line that passes through the points (-4,8) and (-4,-3)
erma4kov [3.2K]

Answer:

(-3-8)/(-4+4)= -11/0= no slope and undefined

Step-by-step explanation:

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3 years ago
I Need Help Please And This Is Due In 1 Hour
alex41 [277]

So the first one is 1 square meter of ceiling, and it says 1 square meter of cieling is 10.75. <em>So the first one is just that, 10.75</em>

The second one says 10 square meters, so just multiply 10.75, by 10.

In which case you get <em>107.5.</em> So that's the answer.

Third one, it gives you how many ceiling tiles you have. So you divide the 100 tiles by 10.75, which gives you 9.30232558, which becomes <em>9.3</em>

I'm sure you can figure out the last one.

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B6%7D%7B3%20%2B%2011i%7D%20" id="TexFormula1" title=" \frac{6}{3 + 11i} " alt=" \f
Lorico [155]

(3+11i)/(3+11i)=1

So that means you can multiply 6/(3+11i) by (3+11i)/(3+11i)

Then 6(3+11i)/1

= 18+66i

7 0
2 years ago
How would you do this as a decimal number ?
Contact [7]

Answer:

-5.875

Step-by-step explanation:

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csf%20%5Clim_%7Bx%20%5Cto%20%5Cinfty%7D%20%5Ccfrac%7B%5Csqrt%7Bx-1%7D-2x%20%7D%7Bx-7%7D" id=
BARSIC [14]
<h3>Answer:  -2</h3>

======================================================

Work Shown:

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}\left(\sqrt{x-1}-2x\right) }{ \frac{1}{x}\left(x-7\right) }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}*\sqrt{x-1}-\frac{1}{x}*2x }{ \frac{1}{x}*x-\frac{1}{x}*7 }\\\\\\

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}}*\sqrt{x-1}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}*(x-1)}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x}-\frac{1}{x^2}}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \frac{ \sqrt{0-0}-2 }{ 1-0 }\\\\\\\displaystyle L = \frac{-2}{1}\\\\\\\displaystyle L = -2\\\\\\

-------------------

Explanation:

In the second step, I multiplied top and bottom by 1/x. This divides every term by x. Doing this leaves us with various inner fractions that have the variable in the denominator. Those inner fractions approach 0 as x approaches infinity.

I'm using the rule that

\displaystyle \lim_{x\to\infty} \frac{1}{x^k} = 0\\\\\\

where k is some positive real number constant.

Using that rule will simplify the expression greatly to leave us with -2/1 or simply -2 as the answer.

In a sense, the leading terms of the numerator and denominator are -2x and x respectively. They are the largest terms for each, so to speak. As x gets larger, the influence that -2x and x have will greatly diminish the influence of the other terms.

This effectively means,

\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 } = \lim_{x\to\infty} \frac{ -2x }{ x} = -2\\\\\\

I recommend making a table of values to see what's going on. Or you can graph the given function to see that it slowly approaches y = -2. Keep in mind that it won't actually reach y = -2 itself.

5 0
3 years ago
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