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Aliun [14]
3 years ago
10

How do you solve "Six less than the quotient of a number and two equals fifteen".

Mathematics
1 answer:
Ainat [17]3 years ago
7 0
X/2 - 6 = 15
x/2 -6 +6 = 15 + 6
x/2 = 21
x/2 × 2 = 21 × 2
x = 42

Check
42 ÷ 2 - 6 = 15
42 ÷ 2 = 21 -6 = 15

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If a data value in a normal distribution has a negative z-score, which of the following must be true?
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The data value must be less than the mean.

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So, Third option is the correct answer. 
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Someone pls also include any work if they can thank you! I’ll mark brainliest!
zysi [14]

Answer/Step-by-step explanation:

A1. Reference angle = 41°

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Hypotenuse = z

Opposite = 8

Thus, applying trigonometric ratio, we would have:

Sin 50 = 8/z

Multiply both sides by z

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Divide both sides by sin 50

z = 8/sin 50

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B1. Reference angle = 49°

Hypotenuse = x

Opposite = 7

Thus, applying trigonometric ratio, we would have:

Sin 49 = 7/x

Multiply both sides by x

x × sin 49 = 7

Divide both sides by sin 49

x = 7/sin 49

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B2. Reference angle = 25°

Hypotenuse = 6

Adjacent = y

Thus, applying trigonometric ratio, we would have:

Cos 25 = y/6

Multiply both sides by 6

6 × cos 25 = y

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B3. Reference angle = 40°

Hypotenuse = z

Adjacent = 8

Thus, applying trigonometric ratio, we would have:

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Multiply both sides by z

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Divide both sides by cos 40

z = 8/cos 40

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