Answer:
The degrees of freedom associated with the critical value is 25.
Step-by-step explanation:
The number of values in the final calculation of a statistic that are free to vary is referred to as the degrees of freedom. That is, it is the number of independent ways by which a dynamic system can move, without disrupting any constraint imposed on it.
The degrees of freedom for the t-distribution is obtained by substituting the values of n1 and n2 in the degrees of freedom formula.
Degrees of freedom, df = n1+n2−2
= 15+12−2=27−2=25
Therefore, the degrees of freedom associated with the critical value is 25.
Answer:
40%
Step-by-step explanation:
The whole rectangle is split into 5 parts. Two out of 5 parts are shaded.
Set up a fraction:

Convert into a decimal:

Multiply the decimal by 100 to get the percent:

So, forty percent of the rectangle is shaded.
Hope this helps.
Answer:
24 days
Step-by-step explanation:
To determine the number of days until they both work out at the gym on the same day again,
Find the lowest common multiples of 4 days and 6 days
Clint (4 days) = 8, 12, 16, 20, 24, 28, 32
Max (6 days) = 12, 18, 24, 30, 36, 42
The lowest common multiple of ,4 days and 6 days is 24 days
Therefore, the number of days until they both work out at the gym on the same day again is 24 days
Answer:
independent: day number; dependent: hours of daylight
d(t) = 12.133 +2.883sin(2π(t-80)/365.25)
1.79 fewer hours on Feb 10
Step-by-step explanation:
a) The independent variable is the day number of the year (t), and the dependent variable is daylight hours (d).
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b) The average value of the sinusoidal function for daylight hours is given as 12 hours, 8 minutes, about 12.133 hours. The amplitude of the function is given as 2 hours 53 minutes, about 2.883 hours. Without too much error, we can assume the year length is 365.25 days, so that is the period of the function,
March 21 is day 80 of the year, so that will be the horizontal offset of the function. Putting these values into the form ...
d(t) = (average value) +(amplitude)sin(2π/(period)·(t -offset days))
d(t) = 12.133 +2.883sin(2π(t-80)/365.25)
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c) d(41) = 10.34, so February 10 will have ...
12.13 -10.34 = 1.79
hours less daylight.
I would say 1 would be the least possible remainder...
11/5 = 2 remainder 1
21/5 = 4 remainder 1
31/5 = 3 remainder 1
and since ur dealing with positive integers (whole numbers), 1 is gonna be the smallest