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vladimir1956 [14]
3 years ago
15

Let f(x)=3x-6. Is f one-to-one? If it is find f^-1, if not explain why.

Mathematics
1 answer:
beks73 [17]3 years ago
8 0

Answer:  Yes,  \bold{f^{-1}(x)=\dfrac{x+6}{3}}

<u>Step-by-step explanation:</u>

f(x) = 3x - 6    is a line so it is a function  because

                      it passes the vertical line test

                              and the horizontal line test

To find the inverse, swap the x's and y's and solve for y

y=3x-6\\\\\\\text{Swap the x's and y's:}\qquad x=3y-6\\\\\text{Add 6 to both sides:}\qquad x+6=3y\\\\\text{Divide both sides by 3:}\qquad \dfrac{x+6}{3}=y

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<img src="https://tex.z-dn.net/?f=Simplify%3A%20%5Cfrac%7B%205%C3%97%2825%29%5E%7Bn%2B1%7D%20-%2025%20%C3%97%20%285%29%5E%7B2n%7
Katen [24]

\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

\rm :\longmapsto\:\dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }

can be rewritten as

\rm \:  =  \: \dfrac{5 \times  { {(5}^{2} )}^{n + 1}  -  {5}^{2}  \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {( {5}^{2} )}^{n + 1} }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

And

\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

So, using this identity, we

\rm \:  =  \: \dfrac{5 \times  {5}^{2n + 2}  - {5}^{2n + 2} }{{5}^{2n + 3 + 1}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 4}  -  {5}^{2n + 2} }

can be further rewritten as

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2}  - 1)}

\rm \:  =  \: \dfrac{4}{25 - 1}

\rm \:  =  \: \dfrac{4}{24}

\rm \:  =  \: \dfrac{1}{6}

<u>Hence, </u>

\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }  =  \frac{1}{6} }}

4 0
2 years ago
Write the expression as the logarithm of a single number or expression.<br>4 In 2+3 In 5​
madreJ [45]

Answer:

ln [2^4 * 5^3]

Step-by-step explanation:

Rewrite 4 ln 2 as ln 2^4 and 3 ln 5 as ln 5^3.

Then 4 In 2+3 In 5 = ln 2^4 + ln 5^3, which in turn becomes

ln [2^4 * 5^3]

6 0
3 years ago
1.
mars1129 [50]

Answer:

yes they are

Step-by-step explanation:

they are both congruent because they are the same shape and size, they are just on opposite sides

(congruent means that 2 objects are the same shape and size)

3 0
3 years ago
Read 2 more answers
What is the y value of -2?
Naily [24]

Answer: -2

Step-by-step explanation:

f(-2) = -2

It is the value of y when x = -2.  I read "-2."

5 0
2 years ago
What is the solution to the equation?<br> c/23 = 2/3
k0ka [10]
46/3 or 15 1/3. Cross multiply and divide your answer
3 0
3 years ago
Read 2 more answers
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