The first one x is greater than and equal to 34
C² = a² + b² - (2ab * cosC)
<span>c² = 10² + 23² - (2 * 10 * 23 * cos95) </span>
<span>c² = 100 + 529 - (460 * -.08715) </span>
<span>c² = 629 - (-40.1) </span>
<span>c² = 669.1 </span>
<span>c = 25.87 </span>
<span>(Sin C) / C = (Sin A) / A </span>
<span>(Sin 95) / 25.87 = SinA / 10, Remember 0 < A < 85 </span>
<span>(10 * Sin95) / 25.87 = Sin A </span>
<span>A = arcsin ((10 * sin95) / 25.87) </span>
<span>A = 22.65º </span>
<span>B = 180 - A - C </span>
<span>B = 180 - 95 - 22.65 </span>
<span>B = 62.35º </span>
<span>I hope this helps. Have a good day.</span>
Answer:
Step-by-step explanation:
Given
Required [Missing from the question]
G(T(x))
We have:
This implies that:
Substitute:
![G(T(x)) = 3[9(x + 6.9)]](https://tex.z-dn.net/?f=G%28T%28x%29%29%20%3D%203%5B9%28x%20%2B%206.9%29%5D)
Open bracket
Due to the difference in the interest rate and the quarterly compounding, Joshua will have $212.24 more than Josiah.
Step-by-step explanation:
Giving the following information:
Joshua:
Initial investment (PV)= $750
Interest rate (i)= 0.0341/4= 0.008525
Number of periods (n)= 18*4= 72 quarters
Josiah:
Initial investment (PV)= $750
Interest rate (i)= 0.0285
Number of periods (n)= 18 years
To calculate the future value of each one, we need to use the following formula:
FV= PV*(1 + i)^n
Joshua:
FV= 750*(1.008525^72)
FV= $1,381.98
Josiah:
FV= 750*(1.0285^18)
FV= $1,169.74
Due to the difference in the interest rate and the quarterly compounding, Joshua will have $212.24 more than Josiah.
