When examining distributions of numerical data, what three components should you look for
1 answer:
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Answer:
The 90% confidence interval for the difference in mean (μ₁ - μ₂) for the two bakeries is; (<u>49</u>) < μ₁ - μ₂ < (<u>289)</u>
Step-by-step explanation:
The given data are;
Bakery A
<em> </em>= 1,880 cal
s₁ = 148 cal
n₁ = 10
Bakery B
<em> </em>= 1,711 cal
s₂ = 192 cal
n₂ = 10
df = n₁ + n₂ - 2
∴ df = 10 + 18 - 2 = 26
From the t-table, we have, for two tails, = 1.706
≈ 178
Therefore, we get;
Which gives;
Therefore, by rounding to the nearest integer, we have;
The 90% C.I. ≈ 49 < μ₁ - μ₂ < 289