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Marat540 [252]
3 years ago
12

Don’t worry bout the answer on the top but can someone help with two and fast ...???

Mathematics
1 answer:
NemiM [27]3 years ago
5 0
I believe it’s $25.50
You might be interested in
What numbers between 49 and 95 that are multiples of 2,3,and9
Alex777 [14]
There are 45 numbers between 49 and 95

Numbers in the fifties: 50,51,52,53,54,55,56,57,58,59

Numbers in the sixties: 60,61,62,63,64,65,66,67,68,69

Numbers in their seventies: 70,71,72,73,74,75,76,77,78,79

Numbers in their eighties: 80,81,82,83,84,85,86,87,88,89

Numbers in their nineties: 90,91,92,93,94

Multiples of 2:

50,52,54,56,58,60,62,64,66,68,70,72,74,76,78,80,82,84,86,88,90,92,94 

Multiples of 3:

51,54,57,60,63,66,69,72,75,78,81,84,87,90

Multiples of 9:

54,63,72,81,90

Notice that all multiples of nine are also multiples of three? That is because three is a factor of nine 


4 0
3 years ago
Need help will give 5 stars.
olga_2 [115]

Answer:

t=0.64

Step-by-step explanation:

h = -16t^2 +4t +4

We want h =0 since it is hitting the ground

0 = -16t^2 +4t +4

Using the quadratic formula

a = -16  b = 4  c=4

-b ± sqrt( b^2 -4ac)

----------------------------

         2a

-4 ± sqrt( 4^2 -4(-16)4)

----------------------------

         2(-16)

-4 ± sqrt( 16+ 256)

----------------------------

         -32

-4 ± sqrt( 272)

----------------------------

         -32

-4 ± sqrt( 16*17)

----------------------------

         -32

-4 ± sqrt( 16) sqrt(17)

----------------------------

         -32

-4 ± 4 sqrt(17)

----------------------------

         -32

Divide by -4

1 ±  sqrt(17)

----------------------------

         8

To the nearest hundredth

t=-0.39

t=0.64

Since time cannot be negative

t=0.64

7 0
3 years ago
Read 2 more answers
Please help me asap i will give brainiest and all my points
Alinara [238K]

Answer:

a. Not Divisible

b. Divisible

c. Divisible

d. Divisible

e. Divisible

Step-by-step explanation:

To find the divisibility we need to follow the PEMDAS rule and check if the total value can be divided by the selected numbers without returning a remainder.

Let's begin with a:

16^{5}+215 by 33

1,048,576 + 215

1,048,791

We now then divide the total amount with 33.

\dfrac{1,048,576}{33}

= 31,781.5454

We can see that the value has a decimal point indicating that the total value divided by 33 will return a remainder. So it is NOT Divisible by 33.

Now let's continue on with the others.

51^{7}-51^{6} by 25

897,410,677,851 - 17,596,287,801

879,814,390,050

We now then divide the total amount with 25.

\dfrac{879,814,390,050}{25}

= 35,192,575,602

The total value did NOT return a decimal point, therefore making the equation true. 51^{7}-51^{6} IS divisible by 25.

Next on we have:

5^{5}-5^{4} +5^{3} by 7

3,125 - 625 + 125

As we know in the PEMDAS rule, that addition comes first. In this situation we have to read the equation from left to right and solve which ever comes first.

2,500 + 125

2,625

We now then divide the total amount with 7.

\dfrac{2,625}{7}

= 375

The total value did NOT return a decimal point, therefore making the equation true. 5^{5}-5^{4} +5^{3} IS divisible by 7.

7^6+7^5-7^4 by 11

117,649+16,807-2,401

134,456-2,401

132,055

We now then divide the total amount with 11.

\dfrac{132,055}{11}

= 12,005

The total value did NOT return a decimal point, therefore making the equation true. 7^6+7^5-7^4 IS divisible by 11.

Last but not the least:

5^{23}-5^{21} by 24

11,920,928,955,078,125-476,837,158,203,125

11,444,091,796,875,000

We now then divide the total amount with 24.

\dfrac{11,444,091,796,875,000}{24}

= 476,837,158,203,125

The total value did NOT return a decimal point, therefore making the equation true. 5^{23}-5^{21} IS divisible by 24.

5 0
3 years ago
Question 5 of 20
Dmitry_Shevchenko [17]
I’m going to say B I could be wrong
3 0
2 years ago
How many true conditional statements may be written using the following statements?
tangare [24]
The answer is A, Hope this helps <3... can i have brainlyest?

4 0
3 years ago
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