the first and last terms of a geometric progression are 2 and 2048 respectively. the sum of the series is 2730. find the number

Question

4 years ago

14

of terms and the common ratio

2 answers:

Salsk061 [2.6K] · Answer 1 · 2021-12-08T09:44:04+03:00

7 0

Answer:

Step-by-step explanation:

dalvyx [7] · Answer 2 · 2021-12-08T11:26:45+03:00

dalvyx [7]4 years ago

4 0

Answer:

n=6

Step-by-step explanation:

Sn=(g1-gn.r)/(1-r)

2730=(2-2948r)/(1-r)

2730(1-r)=2-2048r

2730-2730r=2- 2048r

682r=2729

r=4, common ratio

Now using the formula; Gn=G1.r∧n-1

2048=2.4∧n-1

2048=4∧n-1=2∧2n-2

㏒2 1024=㏒2 2∧2n-2

10=2n-2

n=12/2

=6