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MariettaO [177]
3 years ago
12

Consider the graph that represents the following quadratic equation.

Mathematics
1 answer:
lutik1710 [3]3 years ago
4 0

Answer:

Part 1) The graphs open downward

Part 2) The vertex is the point (-2,5)

Part 3) The axis of symmetry is x=-2

Step-by-step explanation:

step 1

we have

y=-\frac{1}{3}(x+2)^2+5

This is a vertical parabola open downward (because the leading coefficient is negative)

The vertex is a maximum

step 2

The quadratic equation is written in vertex form

y=a(x-h)^2+k

where

(h,k) is the vertex

so

In this problem

The vertex is the point (-2,5)

step 3

The equation of the axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex

The x-coordinate of the vertex is -2

therefore

The axis of symmetry is x=-2

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ella [17]
To dea with absolute values you need to apply the definition of absloute value OR get rid of it by squaring both sides of the equality.
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So, having that in mind, we must split the initial equation into two.
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3 years ago
This right rectangular prism is filled with -foot unit cubes.
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Solve -5(x-7)^2+30=-20
Alex Ar [27]

Answer:

x=7−√10 or x=7+√10

Step-by-step explanation:

−5(x−7)2+30=−20

Step 1: Simplify both sides of the equation.

−5x2+70x−215=−20

Step 2: Subtract -20 from both sides.

−5x2+70x−215−(−20)=−20−(−20)

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Step 3: Use quadratic formula with a=-5, b=70, c=-195.

x=

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2a

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2(−5)

x=

−70±√1000

−10

x=7−√10 or x=7+√10

8 0
3 years ago
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