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mel-nik [20]
3 years ago
10

In which contingency plan testing strategy do individuals participate in a role-playing exercise in which the CP team is present

ed with a scenario of an actual incident or disaster and expected to react as if it had occurred? a. desk check b. structured walk-through c. parallel testing d. simulation
Computers and Technology
2 answers:
Alika [10]3 years ago
6 0

Answer:

b. structured walk-through

Explanation:

  A structured walkthrough is an activity that involves analyzing a system to make sure it meets functional and nonfunctional requirements. Already Validation, is the certification that the system meets customer needs and expectations. The Validation and Verification process are not separate and independent processes.

vesna_86 [32]3 years ago
4 0

Answer:  B. structured walk-through

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The return value is a one-dimensional array that contains two elements. These two elements indicate the rows and column indices
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import java.util.Scanner;  

import java.util.Arrays;  

public class Main  {  

public static void main(String args[])  {  

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public static int[] findmax(int[][] Array2D,int row, int col)   {  

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for(int i =0;i<row;i++){

    for(int j =0;j<col;j++){

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Explanation:

The next two lines import the scanner and array libraries

<em>import java.util.Scanner;   </em>

<em>import java.util.Arrays;   </em>

The class of the program

<em>public class Main  {  </em>

The main method begins here

<em>public static void main(String args[])  {  </em>

The scanner function is called in the program

<em>Scanner input = new Scanner(System.in);</em>

This declares the array row and column

int row, col;

This next instructions prompt the user for rows and get the row input  

System.out.print("Rows: ");    row = input.nextInt();

This next instructions prompt the user for columns and get the column input  

System.out.print("Cols: ");     col = input.nextInt();  

This declares the 2D array

int[][] Array2D = new int[row][col];

This prompts the user for array elements

System.out.print("Enter array elements: ");

The following iteration populates the 2D array

<em> for(int i =0;i<row;i++){    </em>

<em>     for(int j =0;j<col;j++){ </em>

<em>         Array2D[i][j] = input.nextInt();   </em>

<em>     }     } </em>

This calls the findmax function. The returned array of the function is saved in maxarray  

int[] maxarray = findmax(Array2D,row,col);

This prints the row position

System.out.println("Row: "+(maxarray[0]+1));

This prints the column position

System.out.println("Column: "+(maxarray[1]+1));

The main method ends here

}  

The findmax function begins here

public static int[] findmax(int[][] Array2D,int row, int col)   {  

This initializes the maximum to the first element of the array

int max = Array2D[0][0];

This declares maxitem. The array gets the position of the maximum element

int []maxitem = new int [2];

The following iteration gets the position of the maximum element

<em>for(int i =0;i<row;i++){ </em>

<em>     for(int j =0;j<col;j++){ </em>

<em>         if(Array2D[i][j] > max){  </em>

<em>             maxitem[0] = i; </em><em>-- The row position is saved in index 0</em><em> </em>

<em>             maxitem[1] = j;  </em><em>-- The column position is saved in index 1</em><em>} }    } </em>

This returns the 1 d array

return maxitem;  

}  

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