Define a function calc_pyramid_volume with parameters base_length, base_width, and pyramid_height, that returns the volume of a

Question

2 years ago

12

Define a function calc_pyramid_volume with parameters base_length, base_width, and pyramid_height, that returns the volume of a

pyramid with a rectangular base.
Sample output with inputs: 4.5 2.1 3.0
Volume for 4.5, 2.1, 3.0 is: 9.45
Relevant geometry equations:
Volume = base area x height x 1/3
Base area = base length x base width.

given to me
''' Your solution goes here '''
length = float(input())
width = float(input())
height = float(input())
print('Volume for', length, width, height, "is:", calc_pyramid_volume(length, width, height))

Computers and Technology

1 answer:

Sever21 [200] · Answer 1 · 2023-03-12T17:01:54+03:00

The missing segment of the code illustrates the use of functions.

Functions are also referred to as procedures or methods; they are set of instructions that act as one.

The code segment that complete the code in the question is as follows:

def calc_pyramid_volume(length, width, height):

baseArea = length * width

Volume = baseArea * height * 1/3

return Volume

The first line of the code segment declares the function itself

def calc_pyramid_volume(length, width, height):

Then, the base area of the pyramid is calculated

baseArea = length * width

Then, the volume of the pyramid is calculated

Volume = baseArea * height * 1/3

Lastly, the volume is returned to the main method

return Volume

So, the complete code (without comments) is:

def calc_pyramid_volume(length, width, height):

baseArea = length * width

Volume = baseArea * height * 1/3

return Volume

length = float(input())

width = float(input())

height = float(input())

print('Volume for', length, width, height, "is:", calc_pyramid_volume(length, width, height))

See attachment for the sample run