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Mekhanik [1.2K]
3 years ago
10

PLEASE HELP ME!!!!

Mathematics
1 answer:
____ [38]3 years ago
3 0
1. =f
2. =d
3. =c
4. =b
5. =a
6. =e
Hope this helps
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A rectangular park, 90 meters by 60 meters, is to be built on a city block having an area of 9000 m^2. A uniform strip borders a
stealth61 [152]

Answer:

x = 10.52 m

Step-by-step explanation:

Given that,

Length of a park = 90 m

Width of a park = 60 m

Area, A = 9000 m²

A uniform strip borders all four sides of the park for parking. We need to find the width of the strip. Let it is x. Now the area becomes,

(90+2x)(60+2x) = 9000

4x^2 +120x +180x =5400 = 9000\\\\x=10.52\ m

So, the width of the strip is equal to 10.52 m.

8 0
2 years ago
Let f(x) = x2 − 8x + 5. Find f(−1)
rewona [7]

Answer:

14

Step-by-step explanation:

f(x)=x^2-8x+5

now substitute x for -1

f(-1)=(-1)^2-8(-1)+5

now solve

f(-1)=1+8+5

f(-1)=14

there is your answer! hope this helps! :)

5 0
3 years ago
Read 2 more answers
Can someone help me please
ANTONII [103]
B.) 85

They are alternate interior angles so they are the same degree.
3 0
3 years ago
Is the sqrt of 1 - sin^2 theta = cos theta true? If so, in which quadrants does angle theta terminate?
Genrish500 [490]

Answer:

Answer: The answer is option B.

Step-by-step explanation:

Here,

We have,

{ \sin }^{2}  theta \: +  {cos}^{2}theta  = 1

{cos}^{2} \: theta  = 1 -  {sin}^{2}  \: theta

cos \: theta =  \sqrt{1 -  { \sin }^{2}theta }

So, it's true; and it lies in quadrant 1 and 4.

The reason according to the "CAST" rule cos theta is in 1st and 3rd quadrant cos theta is positive.

7 0
3 years ago
Ashley and Kristin are selling wrapping paper for a school fundraiser. Customers can buy rolls of plain wrapping paper and rolls
rodikova [14]

The cost of one roll of plain wrapping paper is $5 and one roll of shiny wrapping paper costs $16.

Step-by-step explanation:

Step 1; Assume that the cost of one roll of plain wrapping paper is $x and a roll of shiny wrapping paper costs $y. so we have the following equations from the given data

4x + 3y = 68, take this as equation 1.

9x + 2y = 77, take this as equation 2

Step 2; We multiply equation 1 with 2 and equation 2 with 3 so we can cancel out the variable y in both equations. By doing this we get

8x + 6y = 136, take this as equation 3,

9x + 2y = 77, this is equation 4.

If we subtract 4 from 3, we cancel out the y variable and can calculate the value of x.

-19x = -103 , x = \frac{-95}{-19} = 5.

Step 3; Substituting this value of x in any of the previous equations we will get x's value. Here this value of y is substituted in equation 1.

4 (5) + 3y = 68, 20 + 3y = 68 , 3y = 48, y= 16.

So we have x = $5 and y = $16.

5 0
3 years ago
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