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deff fn [24]
3 years ago
8

2/3x=10 thankyou for helping me

Mathematics
2 answers:
V125BC [204]3 years ago
7 0
2/3x=10
2=30x
x=0.0667 (3s.f)
Novay_Z [31]3 years ago
6 0
(2/3)x = 10
(3/2)(2/3)x = 10(3/2)
x = 30/2 = 15
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What is the average rate of change of the function over the interval x = 0 to x = 8? f(x)=2x−1/3x+5 Enter your answer, as a frac
max2010maxim [7]

Answer:

15 2/3, or 47/3


Step-by-step explanation:

I'm going to assume, correctly or not, that you actually meant f(x) = 2x^2 - (1/3)x + 5.  Double check on this right now, please.

If I'm right, then evaluate f(x) at x = 0 and x = 8:

f(0) = 5

and

f(8) = 2(8)^2 - (1/3)(8) + 5 = 128 - 8/3 + 5 = 133  - (2 2/3), or:   130 1/3

Then the average rate of change of f(x) = 2x^2 - (1/3)x + 5 over the interval [0,8] is:

                130 1/3 - 5         125 1/3

a. r. c. = ------------------- = ---------------- = 15 2/3, or 47/3

                     8 - 0                  8

3 0
3 years ago
Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-10, 12) and point (5, 3) rounded
Whitepunk [10]

Answer:

<h3>The answer is 17.5 units</h3>

Step-by-step explanation:

Using the distance formula

<h3>d =  \sqrt{ ({x2 - x1})^{2} +  ({y2 - y1})^{2}  }</h3>

the distance between (-10, 12) and (5, 3) is

<h3>d =  \sqrt{ ({5 + 10})^{2}  +  ({3 - 12})^{2} }</h3><h3>d =  \sqrt{ {15}^{2}  + ( { - 9})^{2} }</h3><h3>d =  \sqrt{225 + 81}</h3><h3>d =  \sqrt{306}</h3><h3>d = 3 \sqrt{34}</h3>

d = 17.492855

We have the final answer as

<h3>d = 17.5 units to the nearest tenth</h3>

Hope this helps you

4 0
3 years ago
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3 years ago
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The correct answer is 336 cubic inches.
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Answer:

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Step-by-step explanation:

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