Question

A certain CD-ROM disk can store approximately 6.0 × 102 megabytes of information, where 106 bytes = 1 megabyte. If an average word requires 14 bytes of storage, how many words can be stored on one disk?
A. 4.3 × 107 words
B. 2.1 × 107 words
C. 8.4 × 109 words
D. 2.0 × 109 words

Answer 1

Answer: A. $4.3\times10^7$

Step-by-step explanation:

Given : A certain CD-ROM disk can store approximately $6.0 \times 10^2$  megabytes of information.

1 megabyte = $10^6$ bytes

Then, The storage capacity of CD-ROM disk will be :

$10^6\times 6.0 \times 10^2=6\times10^{6+2}=6\times10^8$  

If an average word requires 14 bytes of storage, then the number of words can be stored :-

$\dfrac{6\times10^8}{14}=0.428571428571\times10^8\approx0.43\times10^8=4.3\times10^7$

Hence,  number of words can be stored = $4.3\times10^7$